An airport has 3 security lines, with each line capable of scanning 290 people per hour. People arrive in front of the security line at the rate of 850 per hour. Make the standard assumption of a Poisson distribution for arrivals and an exponential distribution for service times, and calculate the following:   What is the probability that there are no people in the waiting line? Answer is NOT 0.02.   What is the average length (number of people) in the waiting line? Answer is NOT 41.52.

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A: Mean()=1400standard deviation()=110

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A:

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A: a)P(z>1.38)

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A: XYX.YX2Y2218.0436.084325.4416317.7653.289315.4176418.3873.5216337.8244521.810925475.24621.12126.7236…

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Q: Question 20 The graph illustrates a normal distribution for the prices paid for a particular model…

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A: n=1002

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Q: Having difficulty with parts (a), (b), (c), (d), and (e) on this Intro to Probability and Statistics…

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A: w012P(W=w)0.650.200.015

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