An air-track cart is attached to a spring and completes one oscillation every 5.67 s in simple harmonic motion. At time t = 0.00 s the cart is released at the position x = +0.250 m. What is the position of the cart when t = 29.6 s? Hint: Use the cosine position function. Put your calculator in radians! O x = 0.342 m O x = 0.210 m O x = -0.218 m O x = 0.0461 m

What are the Rotational / Translation Motion equations ?

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ANSWER problem 2.149& 2.150.Use x(0)=.1m and x(dot)(0)=2 as a template for answering the problem stated problem. And note theta tells you which quadrant the tan inverse value will fall in so for example theta with two positive values so the angle inputted will be in quadrant 1 (in the unit circle).Negative value from tan inverse means subtract the inverse tan value from larger value and positive value means add to the smaller value. EX: quad 2 (in the unit circle) smaller value is 90 and larger value is 180