College Physics
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ISBN: 9781305952300
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![An air-filled capacitor consists of two parallel plates, each with an area of \(7.60 \, \text{cm}^2\), separated by a distance of \(1.90 \, \text{mm}\). If a \(23.0 \, \text{V}\) potential difference is applied to these plates, calculate the following:
(a) The electric field between the plates
- Magnitude: \(\_\_\_\_\_\) kV/m
- Direction: [Dropdown menu for selection]
(b) The capacitance
- \(\_\_\_\_\_\) pF
(c) The charge on each plate
- \(\_\_\_\_\_\) pC](https://content.bartleby.com/qna-images/question/021773a5-30bf-4026-94da-b5b931a87d69/810ba3dd-8ab9-4ba8-83ac-813d83ac2f83/isa95ym_processed.png)
Transcribed Image Text:An air-filled capacitor consists of two parallel plates, each with an area of \(7.60 \, \text{cm}^2\), separated by a distance of \(1.90 \, \text{mm}\). If a \(23.0 \, \text{V}\) potential difference is applied to these plates, calculate the following:
(a) The electric field between the plates
- Magnitude: \(\_\_\_\_\_\) kV/m
- Direction: [Dropdown menu for selection]
(b) The capacitance
- \(\_\_\_\_\_\) pF
(c) The charge on each plate
- \(\_\_\_\_\_\) pC
Expert Solution
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Step 1
Assume that the air filled capacitor has two parallel plates.
The area of the plate is A = 7.60 cm2 = 7.60x10-4 m2.
The distance between the plates is d = 1.90 mm = 1.90x10-3 m.
The potential difference applied to the plates is V = 23.0 V.
Assume the permittivity of free space as ε0 = 8.85x10-12 m-3kg-1s4A2.
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