A First Course in Probability (10th Edition)
10th Edition
ISBN: 9780134753119
Author: Sheldon Ross
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Related questions
Question
![**Problem Statement:**
An actress has a probability of getting offered a job after a try-out of 0.11. She plans to keep trying out for new jobs until she gets offered. Assume outcomes of try-outs are independent. Find the probability she will need to attend more than 3 try-outs.
**Solution Explanation:**
To solve this problem, we need to determine the probability that the actress will not get a job offer in the first 3 try-outs and thus will need to attend more than 3 try-outs.
1. **Probability of Not Getting an Offer in One Try-Out:**
- The probability of not getting a job in a single try-out is \(1 - 0.11 = 0.89\).
2. **Probability of Not Getting an Offer in the First Three Try-Outs:**
- Since the outcomes are independent, we multiply the probabilities of not getting an offer in each of the first three try-outs:
\[
(0.89)^3 = 0.89 \times 0.89 \times 0.89
\]
3. **Calculation:**
- Performing the calculation gives:
\[
(0.89)^3 = 0.704969
\]
Therefore, the probability that she will need to attend more than 3 try-outs is approximately 0.705, or 70.5%.](https://content.bartleby.com/qna-images/question/3caf0467-ca0e-4770-b0d8-25bdaac915d0/6530084a-f118-4188-9fbf-b3b71025a1af/8g0xcnn_processed.png)
Transcribed Image Text:**Problem Statement:**
An actress has a probability of getting offered a job after a try-out of 0.11. She plans to keep trying out for new jobs until she gets offered. Assume outcomes of try-outs are independent. Find the probability she will need to attend more than 3 try-outs.
**Solution Explanation:**
To solve this problem, we need to determine the probability that the actress will not get a job offer in the first 3 try-outs and thus will need to attend more than 3 try-outs.
1. **Probability of Not Getting an Offer in One Try-Out:**
- The probability of not getting a job in a single try-out is \(1 - 0.11 = 0.89\).
2. **Probability of Not Getting an Offer in the First Three Try-Outs:**
- Since the outcomes are independent, we multiply the probabilities of not getting an offer in each of the first three try-outs:
\[
(0.89)^3 = 0.89 \times 0.89 \times 0.89
\]
3. **Calculation:**
- Performing the calculation gives:
\[
(0.89)^3 = 0.704969
\]
Therefore, the probability that she will need to attend more than 3 try-outs is approximately 0.705, or 70.5%.
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution
Trending nowThis is a popular solution!
Step by stepSolved in 2 steps with 2 images
Knowledge Booster
Similar questions
- A student has a 40% chance of getting a particular professor for a class. What are the odds of getting the professor?arrow_forwardThe probability of a grand piano selling for more than $58,600 is 0.2727. As these pianos sell across the country, what is the probability that the first piano that sells for more than $58,600 is the fourth piano?arrow_forwardDuring the second round of the 1989 U.S. Open golf tournament, four golfers scored a hole in one on the sixth hole. The odds of a professional golfer making a hole in one are estimated to be 3,708 to 1, so the probability is 1/3,709. There were 155 golfers participating in the second round that day. Estimate the probability that four golfers would score a hole in one on the sixth hole.arrow_forward
- A newspaper report states that the probability of snow is .3. After calling the airport you are told that if it snows, the probability that your plane will take off on time is 0.40. If it does not snow, the probability that your plane takes off on time is 0.90. Find the probability of your plane taking off on time.arrow_forwardThe probability that a high school student get less than 5 hours of sleep on average is 35.2%. The probability that a randomly chosen high school student gets less than 5 hours of sleep on average AND is in the school's band is 19.5%. What is the probability that a high school student is in band given that they get less than 5 hours of sleep on average?arrow_forwardAccording to a survey, the probability that a family owns 2 cars if its annual income greater than $35000 is 0.75. Of the households surveyed 60 % had incomes over $ 35000 and 52 % had 2 cars? What is the probability that a family has 2 cars and an income over $35000 a year?arrow_forward
- A high school baseball player has a 0.171 batting average. In one game, he gets 7 at bats. What is the probability he will get at least 5 hits in the game?arrow_forwardA high school baseball player has a 0.246 batting average. In one game, he gets 8 at bats. What is the probability he will get at least 5 hits in the game?arrow_forwardA person conducting telephone surveys must get 3 more completed surveys before their job is finished. On each random phone call, there is a 20% chance of completing the phone survey. What is the probability that it takes 5 calls or more to complete the 3rd survey?arrow_forward
- Suppose a basketball player has a 84% of making his free throws. Assume that the free throws are independent of one another. Suppose this player gets to shoot three free throws, what is the probability that he misses at least 1 free throw?arrow_forwardIn a classroom of 27 students, there are 17 girls and 10 males. Mr. Stover wants to randomly select a student but states that the probability of selecting a female student is a lot larger than selecting a male student. Is this assumption correct? Explain your answer.arrow_forwardThe average number of field mice per acre in a wheat field is estimated to be 1.2. Find the probability that more than one field mice are found on at least one of the next 5 acres inspected.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- A First Course in Probability (10th Edition)ProbabilityISBN:9780134753119Author:Sheldon RossPublisher:PEARSON
A First Course in Probability (10th Edition)
Probability
ISBN:9780134753119
Author:Sheldon Ross
Publisher:PEARSON