College Physics
College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
Bartleby Related Questions Icon

Related questions

bartleby

Concept explainers

Question
### Kinetic Energy and Work Done

**Problem Statement:**

An accelerating object of mass \( m = 2 \) kg is fired with an initial speed \( v_i = 8 \) m/s at a starting point. If its kinetic energy at its final destination is \( K.E = 268 \) J, what is the resultant work (in joules) done on the object?

**Options:**

A. 204  
B. None  
C. 704  
D. 1004  
E. 1204  

**Explanation and Solution:**

To solve for the resultant work done on the object, we can use the Work-Energy Theorem, which states that the work done on an object is equal to the change in its kinetic energy.

The kinetic energy (K.E) of an object is given by:
\[ K.E = \frac{1}{2}mv^2 \]

1. Calculate the initial kinetic energy (\( K.E_i \)) at the starting point:
\[ K.E_i = \frac{1}{2} m v_i^2 \]
\[ K.E_i = \frac{1}{2} \times 2 \times (8)^2 \]
\[ K.E_i = 1 \times 64 \]
\[ K.E_i = 64 \text{ J} \]

2. Given the final kinetic energy (\( K.E_f \)) at the final destination is 268 J.

3. Calculate the work done (W) on the object:
\[ W = K.E_f - K.E_i \]
\[ W = 268 \text{ J} - 64 \text{ J} \]
\[ W = 204 \text{ J} \]

Therefore, the correct answer is option A: 204 J.
expand button
Transcribed Image Text:### Kinetic Energy and Work Done **Problem Statement:** An accelerating object of mass \( m = 2 \) kg is fired with an initial speed \( v_i = 8 \) m/s at a starting point. If its kinetic energy at its final destination is \( K.E = 268 \) J, what is the resultant work (in joules) done on the object? **Options:** A. 204 B. None C. 704 D. 1004 E. 1204 **Explanation and Solution:** To solve for the resultant work done on the object, we can use the Work-Energy Theorem, which states that the work done on an object is equal to the change in its kinetic energy. The kinetic energy (K.E) of an object is given by: \[ K.E = \frac{1}{2}mv^2 \] 1. Calculate the initial kinetic energy (\( K.E_i \)) at the starting point: \[ K.E_i = \frac{1}{2} m v_i^2 \] \[ K.E_i = \frac{1}{2} \times 2 \times (8)^2 \] \[ K.E_i = 1 \times 64 \] \[ K.E_i = 64 \text{ J} \] 2. Given the final kinetic energy (\( K.E_f \)) at the final destination is 268 J. 3. Calculate the work done (W) on the object: \[ W = K.E_f - K.E_i \] \[ W = 268 \text{ J} - 64 \text{ J} \] \[ W = 204 \text{ J} \] Therefore, the correct answer is option A: 204 J.
Expert Solution
Check Mark
Knowledge Booster
Background pattern image
Physics
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
Text book image
College Physics
Physics
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
Text book image
University Physics (14th Edition)
Physics
ISBN:9780133969290
Author:Hugh D. Young, Roger A. Freedman
Publisher:PEARSON
Text book image
Introduction To Quantum Mechanics
Physics
ISBN:9781107189638
Author:Griffiths, David J., Schroeter, Darrell F.
Publisher:Cambridge University Press
Text book image
Physics for Scientists and Engineers
Physics
ISBN:9781337553278
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Text book image
Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:9780321820464
Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:Addison-Wesley
Text book image
College Physics: A Strategic Approach (4th Editio...
Physics
ISBN:9780134609034
Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:PEARSON