### Kinetic Energy and Work Done**Problem Statement:**An accelerating object of mass \( m = 2 \) kg is fired with an initial speed \( v_i = 8 \) m/s at a starting point. If its kinetic energy at its final destination is \( K.E = 268 \) J, what is the resultant work (in joules) done on the object?**Options:**A. 204 B. None C. 704 D. 1004 E. 1204 **Explanation and Solution:**To solve for the resultant work done on the object, we can use the Work-Energy Theorem, which states that the work done on an object is equal to the change in its kinetic energy.The kinetic energy (K.E) of an object is given by:\[ K.E = \frac{1}{2}mv^2 \]1. Calculate the initial kinetic energy (\( K.E_i \)) at the starting point:\[ K.E_i = \frac{1}{2} m v_i^2 \]\[ K.E_i = \frac{1}{2} \times 2 \times (8)^2 \]\[ K.E_i = 1 \times 64 \]\[ K.E_i = 64 \text{ J} \]2. Given the final kinetic energy (\( K.E_f \)) at the final destination is 268 J.3. Calculate the work done (W) on the object:\[ W = K.E_f - K.E_i \]\[ W = 268 \text{ J} - 64 \text{ J} \]\[ W = 204 \text{ J} \]Therefore, the correct answer is option A: 204 J.

Given data: Mass m =2 kg Velocity v=8 m/s2. Final Kinetic energy =268 J

An accelerating object of mass m=2 kg is fired with an initial speed v=8 m/s at a starting point. If its kinetic energy at its final destination is K.E=268 J. What is the resultant work (in joules) done on the object? A. 204 O. B. None C. 704 D. 1004 E. 1204

An accelerating object of mass m=2 kg is fired with an initial speed v=8 m/s at a starting point. If its kinetic energy at its final destination is K.E=268 J. What is the resultant work (in joules) done on the object? A. 204 O. B. None C. 704 D. 1004 E. 1204

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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