Chemistry
Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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**Problem Statement:**

An 80.0 g sample of a gas was heated from 25 °C to 225 °C. During this process, 346 J of work was done by the system and its internal energy increased by 8915 J. What is the specific heat of the gas?

**Solution:**

To find the specific heat capacity (\(c\)) of the gas, we use the formula relating heat (\(q\)), mass (\(m\)), specific heat capacity (\(c\)), and change in temperature (\(\Delta T\)):

\[
q = mc\Delta T
\]

The change in internal energy (\(\Delta U\)) relates to heat added and work done:

\[
\Delta U = q + W
\]

Where:
- \(\Delta U = 8915 \, \text{J}\) (change in internal energy)
- \(W = -346 \, \text{J}\) (work done by the system, negative because work is done by the gas)

From the equation \(\Delta U = q + W\), solve for \(q\):

\[
q = \Delta U - W = 8915 \, \text{J} + 346 \, \text{J} = 9261 \, \text{J}
\]

Now substitute \(q\) into the specific heat formula:

\[
9261 \, \text{J} = 80.0 \, \text{g} \cdot c \cdot (225 - 25) \, \text{°C}
\]

\[
9261 = 80.0 \cdot c \cdot 200
\]

Solve for \(c\):

\[
c = \frac{9261}{80.0 \cdot 200} = \frac{9261}{16000} \approx 0.579 \, \text{J/(g·°C)}
\] 

Therefore, the specific heat capacity of the gas is approximately \(0.579 \, \text{J/(g·°C)}\).
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Transcribed Image Text:**Problem Statement:** An 80.0 g sample of a gas was heated from 25 °C to 225 °C. During this process, 346 J of work was done by the system and its internal energy increased by 8915 J. What is the specific heat of the gas? **Solution:** To find the specific heat capacity (\(c\)) of the gas, we use the formula relating heat (\(q\)), mass (\(m\)), specific heat capacity (\(c\)), and change in temperature (\(\Delta T\)): \[ q = mc\Delta T \] The change in internal energy (\(\Delta U\)) relates to heat added and work done: \[ \Delta U = q + W \] Where: - \(\Delta U = 8915 \, \text{J}\) (change in internal energy) - \(W = -346 \, \text{J}\) (work done by the system, negative because work is done by the gas) From the equation \(\Delta U = q + W\), solve for \(q\): \[ q = \Delta U - W = 8915 \, \text{J} + 346 \, \text{J} = 9261 \, \text{J} \] Now substitute \(q\) into the specific heat formula: \[ 9261 \, \text{J} = 80.0 \, \text{g} \cdot c \cdot (225 - 25) \, \text{°C} \] \[ 9261 = 80.0 \cdot c \cdot 200 \] Solve for \(c\): \[ c = \frac{9261}{80.0 \cdot 200} = \frac{9261}{16000} \approx 0.579 \, \text{J/(g·°C)} \] Therefore, the specific heat capacity of the gas is approximately \(0.579 \, \text{J/(g·°C)}\).
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