An 2m. long beam is on hinged at its left end and on fixed support at its right end. Its flexural capacity is 610 kN.m. whilte its web shear capacity is 642 kN. Beam flexural rigidity is 52x 1012 N.mm². #1 What is the allowable uniformly distributed load on the beam so that the flexural capacity is not exceeded? #2 Based on web shear capacity, what is the allowable uniformly distributed load (kN/m)? #3 When the support at the left end is removed, a cantilever beam results. How much should the beam be cambered at the free end to offset the end deflection if the load W210 kN/m?

The section of a Super-T prestressed concrete girder is shown below. The girder is simply supported on a span of 7.0 m and are pre-tensioned with total initial force of 825 kN from low-relaxation strands. The girder supports a total dead load of 2 kPa and live load of 6 kPa. There is a loss of prestress of 0.2 at service loads. Assume "-" for compression and "+" for tension. Hint: Assume tributary width is equal to flange width. Properties of the section: A = 100,000 mm2 INA = 940 x 106 mm4 All measurements in the drawings are in millimeters. 1. What is the stress, in MPa, at the top fibers of the girder at end span due to initial prestressing force only? 2. What is the stress, in MPa, at the bottom fibers of the girder at midspan due to initial prestressing force only? 3. What is the stress, in MPa, at the top fibers of the girder at end span due to prestressing force and service loads? 4. What is the stress, in MPa, at the bottom fibers of the girder at midspan due to prestressing…

The allowable shear stress is τallow=895 psi�allow=895 psi. The supports at A� and B� are smooth