An 26 g rifle bullet traveling at 270 m/s buries itself in a 5.4 kg pendulum hanging on a 2 m long string, which makes he pendulum swing upward in an arc. Determine the maximum vertical displacement of the pendulum (height). (g = 9.8 M/s^2

3. A simple pendulum is suspended from the ceiling by means of a string of length 1.60 m. Now you start with the pendulum at 16.6 degrees with respect to the vertical, but rather than releasing it from rest, you give it a push downward. It swings to the other side, and reaches a maximum angle of 55.4 degrees with respect to the vertical. What must have been the initial speed of the pendulum just after you pushed it?    4.78 m/s    3.50 m/s    3.68 m/s    1.14 m/s

In a ballistic pendulum, the following data is given: m = 60.5 +/- 0.1 g for mass M = 210 +/- 10 g for pendulum mass θ = 35º +/- 1º for maximum deflection angle r= 30.0 +/- 0.1cm  for distance from the pivot to the center of the pendulum bob  Calculate v0 using the equations v0 = ((M + m)/m)(2gh)1/2 and h = r (1 - cosθ) [height maximum deflection].

H2. A simple pendulum has a particle of mass m at the end of a light rod of length 1. The other end of the rod is attached to a fixed point O, at the origin of polar coordinates (r, 0). The particle is at position (r, 0) with 0 = 0 corresponding to the particle being vertically below O. (a) Use the formulae for acceleration in polar coordinates, a = ( − rġ²) + (2rė + rö)ê to show that cos 0 + A, 8 T = mg cos 0 + mlė², where T' is the tension in the rod. Use the relation (0²) = 200 to deduce that 2g ². = 1 and 0 == sin sin 0, (1) where A is a constant. If the particle is instantaneously at rest ( = 0) when the rod is horizontal, find and T when the rod is vertical. How does the tension in the vertical position (which is also the maximal tension) depend on the rod's length /? (b) Assume the particle is subject to linear air resistance av. Use the expression of the velocity in polar coordinates v=rf+rẻÔ (2) together with (1) to write the equations of motion in polar coordinates. Show…

NOTE: The answer of 85.715 rpm was given to me and was incorrect. What is the correct answer?

A pendulum is 0.341m long and has a period of 3.207s. The pendulum is on an unknown planet. What is the gravity of the unknown planet in m/s2?

4. After landing on an unfamiliar planet, a space explorer constructs a simple pendulum of length 49.0 cm . The explorer finds that the pendulum completes 90.0 full swing cycles in a time of 145s. What is the magnitude of the gravitational acceleration on this planet?

tion - A pendulum 4.03 m in length swings through 47 degrees. Calculate the curvilinear distance (s) traveled by its tip to 2 decimal places. Answer: pe here to search E D da. D R F Bi T G 6 B Y & H N U J 8 1 M N 9 K S Ps L >> P Next page ASXXCTD +1.33% Fint

4. A simple pendulum is suspended from the ceiling by means of a string of length 1.44 m long. Suppose you start with the pendulum hanging vertically, at rest. You then give it a push so that it starts swinging with a speed of 1.53 m/s. What maximum angle (in degrees) will it reach, with respect to the vertical, before falling back down?      32.9 degrees      28.2 degrees      23.5 degrees      16.5 degrees