An 13.6l sample of gas is determined to contain 0.80 mol Ar. At the same temperature and pressure, how many moles of gas would there be in a 45L sample?
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A: PV = nRT T=PVnR T=5.8*10-3*1.6*1063.6*8.31 T= 310.202K
An 13.6l sample of gas is determined to contain 0.80 mol Ar. At the same temperature and pressure, how many moles of gas would there be in a 45L sample?
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