Aluminium alloy AA7475 is applied as a high strength aluminium sheet for aerospace. In preparation for its use a number of tests are carried out on sample sheets including analysis of fracture toughness. A central through-thickness crack is introduced in the sheets. The suppliers of the material quote a fracture toughness of 42 MPa m1/2. Dimensions of the sheet are demonstrated in Figure Q3, where Width W = 50 mm and thickness t = 1 mm. A stress of 447 MPa is applied. Calculate the critical crack half length ac. You may assume a value of Y = 1. Answers should be given in metres (without units) to 2 significant figures Stress intensity K = Υσ πα t W 2a Į F Figure Q3 - a plate of width W containing a central through-thickness crack of length 2a

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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Aluminium alloy AA7475 is applied as a high strength aluminium sheet for aerospace. In preparation for its use a number of tests are carried out on sample
sheets including analysis of fracture toughness. A central through-thickness crack is introduced in the sheets. The suppliers of the material quote a fracture
toughness of 42 MPa m1/2. Dimensions of the sheet are demonstrated in Figure Q3, where Width W = 50 mm and thickness t = 1 mm. A stress of 447 MPa is
applied. Calculate the critical crack half length ac. You may assume a value of Y = 1.
Answers should be given in metres (without units) to 2 significant figures
Stress intensity
K = Υσ πα
t
W
2a
↓
F
F
Figure Q3- a plate of width W containing a central through-thickness crack of length 2a
Transcribed Image Text:Aluminium alloy AA7475 is applied as a high strength aluminium sheet for aerospace. In preparation for its use a number of tests are carried out on sample sheets including analysis of fracture toughness. A central through-thickness crack is introduced in the sheets. The suppliers of the material quote a fracture toughness of 42 MPa m1/2. Dimensions of the sheet are demonstrated in Figure Q3, where Width W = 50 mm and thickness t = 1 mm. A stress of 447 MPa is applied. Calculate the critical crack half length ac. You may assume a value of Y = 1. Answers should be given in metres (without units) to 2 significant figures Stress intensity K = Υσ πα t W 2a ↓ F F Figure Q3- a plate of width W containing a central through-thickness crack of length 2a
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