Answered: A l ( N O 3 ) 3 ( s ) ⟶ A l 3 + ( a q )…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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A l ( N O 3 ) 3 ( s ) ⟶ A l 3 + ( a q ) + 3 N O 3 − ( a q )

Calculate the moles of nitrate ions in 20.77mL of a 0.71M aluminum nitrate solution. Hint: multiply by the mole ratio.

Expert Solution

Step 1

Al(NO₃)₃ (s) ⟶ Al³⁺ (aq) + 3NO³⁻ (aq)

To calculate the number of moles of nitrate ions in 20.77 ml of a 0.71 M aluminum nitrate.

Step 2

1 ml equals to 10^-3 L therefore 20.77 ml equals to 20.77×10^-3 L

Calculate the number of moles of aluminum nitrate in 20.77×10^-3 L solution

$\begin{array}{l} Number of moles = (Concentration) (Volume of solution) \\ Number of moles = (0.7 M) (20.77 \times 10^{- 3} L) \\ Number of moles = 14.539 \times 10^{- 3} mol \end{array}$

Thus, number of moles of aluminum nitrate in the solution is 14.539×10^-3 mol

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