all parts of the same question ### Reaction 3:In this chemical reaction, the starting compound is reacted with hydrochloric acid (HCl, 3M concentration) to form an intermediate product E. Subsequently, E is reacted with sodium hydroxide (NaOH, 6M concentration) to produce the final product F.#### Chemical Structures:- **Starting Compound**: A bicyclic structure with a carbonyl group (C=O).- **Reagents**: - **HCl (3M)**: Hydrochloric Acid in 3 molar concentration. - **NaOH (6M)**: Sodium Hydroxide in 6 molar concentration.#### Possible Products Illustrated:1. **Compound 1**: - Structure: A bicyclic structure with an additional carboxyl group (C=O) and hydroxyl group (OH). 2. **Compound 2**: - Structure: A bicyclic structure with two hydroxyl groups (dihydroxy).3. **Compound 3**: - Structure: A bicyclic ketone with a side chain containing an ethyl ester group.4. **Compound 4**: - Structure: A bicyclic structure with an amino group (NH2) attached to the aromatic ring.5. **Compound 5**: - Structure: A sodium salt (ONa) of a bicyclic carboxylate.6. **Compound 6**: - Structure: A simple bicyclic ketone.7. **Compound 7**: - Structure: A bicyclic structure with a single hydroxyl group (OH). 8. **Compound 8**: - Structure: A bicyclic structure with an amino group (NH2) and a hydroxyl group (OH).9. **Compound 9**: - Structure: A chlorinated derivative with a carbonyl group.These structures represent possible outcomes of the reaction sequence leading to product F. **Educational Content: Organic Chemistry Reactions****Task 14:**Complete each of the following reactions by selecting the best matching structure from the structures labeled 1-9.---**Reaction 1:**Starting Materials:- Reactant: A compound depicted with a benzene ring attached to a hydroxyl group (phenol).- Reagent: NaOH (3M)Process:- A compound is labeled as "A" is formed.- Following, HCl (6M) is added to give compound "B".Options for A and B:1. A phenol structure.2. A bicyclic compound with two hydroxyl groups.3. An ethoxybenzene compound.4. A benzene ring with an aminomethyl group.5. A sodium phenoxide ion.6. A naphthalene structure.7. A naphthol structure.8. An aminophenol compound.9. A chloro-benzoyl chloride compound.---**Reaction 2:**Starting Materials:- Reactant: A compound with an aniline derivative (ethyl attached).- Reagent: HCl (3M)Process:- Formation of compound "C".- Subsequently, NaOH (6M) is applied to yield compound "D".Options for C and D:The same options listed in Reaction 1.**Diagrams Explanation:**- The diagrams depict different organic structures with functional groups such as hydroxyl, amino, and acyl groups. They represent potential products or intermediates in chemical reactions involving substitutions or ion formations.Explore the relation between reactants, reagents, and possible products based on the functional groups and reactivity patterns common in organic chemistry!**Notes:**- Consider acidity and basicity when predicting the outcomes.- Examine any possible structural changes or stable ions that could be formed with the given reagents.

Strong acids and strong bases are the ones that entirely dissociate to give H+ ion and OH- ion respectively. HCl is a strong acid that completely dissociates to release H+ ion in solution while NaOH is a strong base that completely dissociates to release OH- ion in solution.In the first reaction, NaOH abstracts the hydrogen atom of carboxylic acid and forms sodium salt of carboxylate which then reacts with HCl to form acid again.In the second reaction, first protonation of oxygen of carbonyl group takes place, and then the elimination of C2H5OH takes place to form the final product.In the third reaction, first protonation of oxygen of carbonyl group takes place and then Cl- ion and NaOH attack to form the final product.