Consider the elliptic curve group based on the equationwhere a =1405, b = 2011, and p = 2531.We will use these values as the parameters for a session of Elliptic Curve Diffie-Hellman Key Exchange. We will use P = (0,98) as asubgroup generator.You may want to use mathematical software to help with the computations, such as the Sage Cell Server (SCS).On the SCS you can construct this group as:G=EllipticCurve(GF(2531),[1405,2011])Here is a working example.(Note that the output on SCS is in the form of homogeneous coordinates. If you do not care about the details simply ignore the 3rdcoordinate of output.)62Alice selects the private key 41 and Bob selects the private key 20.What is A, the public key of Alice?y² = x³ + ax+b mod pWhat is B, the public key of Bob?2472After exchanging public keys, Alice and Bob both derive the same secret elliptic curve point TAB. The shared secret will be the x-coordinateof TAB. What is it?

To compute the public key A of Alice, we need to compute A = 8P, where P = (0, 98) is the generator.…

Alice selects the private key 41 and Bob selects the private key 20. What is A, the public key of Alice? 62 What is B, the public key of Bob? 2472 After exchanging public keys, Alice and Bob both derive the same secret elliptic curve point TAB. The shared secret will be the x-coordinat

Alice selects the private key 41 and Bob selects the private key 20. What is A, the public key of Alice? 62 What is B, the public key of Bob? 2472 After exchanging public keys, Alice and Bob both derive the same secret elliptic curve point TAB. The shared secret will be the x-coordinat

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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