Algorithm to Divide-Count( ) // Calculate the Box Occupancies of Each Grid Level Input: A ∈ Rm × n // A dataset of m points and n features Output: C//Cj,keyi contains the box occupancy of class j for the grid cell indexed by keyi
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Input: A ∈ Rm × n // A dataset of m points and n features
Output: C//Cj,keyi contains the box occupancy of class j for the grid cell indexed
by keyi
1: D
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- javascript only: You have been assigned to work with an undersea explorer who is attempting to identify and map undersea trenches. The explorer has provided you with several data sets. Depending on the scan, the provided matrix may be larger or smaller, but it will always be rectangular. Your task is to determine if a given data set contains a trench by comparing each node and their neighbors and determining if there is a pattern that matches the defined properties of a trench. Neighbors are considered to be nodes that are directly above, below, or to the side. No diagonals! A trench has the following three properties: It has a length of three or more nodes that are neighbors. Each node in the trench must be deeper than -5. Trenches may not branch into (any form of) a "T" shape. A node with more than two neighbors will result in branching "T" shape. // Example 1 sonar = [ [-5,-5,-5,-5,-5], [-5,-8,-8,-9,-7], [-5,-5,-5,-5,-8], [-5,-5,-5,-5,-5] ]In elementwise multiplication A.*B each value in one matrix is paired up with a buddy value in the other and they are multiplied together.In matrix multiplication A*B each row in matrix A is dot-producted with each column in matrix B.The value in the upper left corner of the matrix C is the same as which of the following?C = A*B; options: A(1,1) * B(1,1) dot(A(1,:),B(:,1)) A = [3 1; 5 2];B = [1 -1; 4 0];C = A*Bthe value in the upper left corner of the matrix C is which of the following? % Starting with this code:a = [1 2 3]b = [-1 0 1]% All of the following are identical, except which one? Question 4 options: dot(a,b) a*transpose(b) b*transpose(a) sum(a.*b) They are all identical Fill in the blank to calculate the dot product of amounts and costs.amounts = [2 1 2 5 1]costs = [3.5 1.25 4.25 1.55 3.15]____________ Question 5 options:…6. Numpy.linalg https://numpy.org/doc/stable/reference/generated/numpy.linalg. solve.html. Generate a random, square matrix and random vector using numpy and then solve using numpy.linalg.solve(). Confirm it is a solution using 'A.dot (x)' where x is the solution from solve(). import numpy as np n=100 Numpy has its own black-box linear system solver numpy.linalg.solve(): A=np.random.rand (n,n) b=np.random.rand (n,1) I
- There is a data set that describes the email contacts between people in a University department. The data set is as follows: 0 1 0 2 0 6 1 0 1 3 1 5 2 0 2 4 3 1 3 5 3 6 4 2 4 5 5 1 5 3 5 4 6 0 6 3 There are totally 7 ids, representing 7 individuals. The two columns are the ids of persons. The id pair in a row represents an email contact relationship between the node pairs. For example, the first row ‘0 1’ means an individual with id 0 and an individual with id 1 have an email contact. All the individuals and their relationship constitute an email contact network, which is a graph in data structure. Based on the data set, please implement the following tasks: Establish a graph data structure using the adjacent list method. Source code: Running snapshot: Let node 0 as the origin and do the BFS traverse of the graph. Print out the BFS traverse…• C=numpy.add(A, B): Add two matrices A and B and store result in C.• C=numpy.subtract(A, B): Subtract matrix B from matrix A and store result in C.• C=numpy.divide(A, B): Divide matrix A by matrix B and store result in C.• C=numpy.multiply(A, B): Multiply matrix A by matrix B and store result in C.• C=numpy.sum(A): Form the sum of elements of matrix A and store result in c ∈ R.• C=numpy.sum(A, axis = 0): Form the column wise summation of matrix A andstore result in vector C.• C=numpy.sum(A, axis = 1): Form the row wise summation of matrix A, storeresult in vector C.Write Python code to shows the implementation of these methods in asample matrixQ1. Design a generic matrix multiplier. Here ‘generic’ means the design should work for anymatrix multiplication X∙Y = Z, where the matrices X, Y, and Z are of sizes a×b, b×c, and a×crespectively. Now, pick a, b, c from the last three digits of your roll number. ( If any of the digitsis 0, take 3 instead of it; if two digits are 0s, then take 3 for the first 0, and 5 for the second 0)For Example, if the last three digits are 123 then a = 1, b = 2, and c = 3; if the last three digitsare 204 then a = 2, b = 3, c = 4; f the last three digits are 100 then a = 1, b = 3, c = 5.
- Q2. Given the graph below implement an array based storage backend for a map application to leverage for the implementation of shortest possible path analysis. Dallas 200 1300 200 Austin Washington Denver 1400 Atlanta 160 800 800 Chicago Houston 400 400 006Data Mining A two-dimensional set x = {(6, 3); (12, 4); (18, 10); (24, 11); (30, 12); (42, 20); (48, 25)}. Please use K Means Clustering to cluster the above data into two clusters; by placing each point to the nearest centroid (using the City Block / Manhattan distance formula) with the initial centroid C1 = (18, 2); and C2 = (45, 10).The Burrows-Wheeler transform (BWT) is a transformation that is used in data compression algorithms, including bzip2, and in high-throughput sequencing in genomics. Write a SuffixArray client that computes the BWT in linear time, as follows: Given a string of length N (terminated by a special end-of-file character $ that is smaller than any other character), consider the N-by-N matrix in which each row contains a different cyclic rotation of the original text string. Sort the rows lexicographically. The Burrows-Wheeler transform is the rightmost column in the sorted matrix. For example, the BWT of Mississippi is ipssm$pissii. The Burrows-Wheeler inverse transform (BWI) inverts the BWT. For example, the BWI of ipssm$pissii is mississippi$. Also write a client that, given the BWT of a text string, computes the BWI in linear time.
- Given the pseudocode fragment below to find the largest number in a 2D matrix, drag and drop the correct code fragments/lines onto their correct positions/order to complete a correct algorithm. Start 2 3 4 6 7 |10 11 12 stop isFound=true Print maxNumber ENDCASE maxNumber =55 if(myValue> maxNumber) then endif ENDDO//end outer LOOP maxNumber =myValue maxNumber=Matrix[0][0] myValue=0 DO (row=0 to maxNumber.length-1) DO (column=0 to maxNumber.length-1) myValue= maxNumber[row][ column] ENDDOllend inner LOOPIn which of the following cases, linked list implementation of sparse matrices consumes the same memory space as the conventional way of storing the entire array? A. 5x6 matrix with 9 non-zero entries B. 5x6 matrix with 10 non-zero entries C. Efficient in accesing an entry D. Efficient if the sparse matrix is a band matrixIn pythion with numpy I have code in a for loop that creates a vecor of 12 elements:x = 1 2 3 4 5 6 7 8 9 10 11 12 The loop iterates 10 times. The second iteration generates a new vector x = 12 11 10 9 8 7 6 5 4 3 2 1 etc. At the end of the loop I need to have a 12 X 10 matrix x x x x x x x x x x x x x x x x x x x xx x x x x x x x x x x x x x x x x x x xx x x x x x x x x x x x x x x x x x x xx x x x x x x x x x x x x x x x x x x xx x x x x x x x x x x x x x x x x x x xx x x x x x x x x x x x x x x x x x x x I cannot figure out how to createa matrix where it takes the output and uses the output as row
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