
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN: 9780134463216
Author: Robert F. Blitzer
Publisher: PEARSON
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Question
![**Circle Equation Problem**
**Objective**: Find the standard form of the equation of a circle with the following properties:
- **Center**: \((-9, -7)\)
- **Tangent to the x-axis**
**Task**: Type the standard form of the equation of this circle.
*(Type your equation in the provided answer box.)*
---
**Explanation**:
For a circle tangent to the x-axis, the vertical distance from the center to the x-axis is equal to the radius. Since the center is at \((-9, -7)\), and the y-coordinate is \(-7\), the radius is \(7\).
The standard form of the equation of a circle is:
\[
(x - h)^2 + (y - k)^2 = r^2
\]
Where \( (h, k) \) is the center of the circle and \( r \) is the radius.
For this problem, \( h = -9 \), \( k = -7 \), and \( r = 7 \).
Thus, the standard form of the circle's equation is:
\[
(x + 9)^2 + (y + 7)^2 = 49
\]](https://content.bartleby.com/qna-images/question/323a188d-72c2-4f77-bbb3-3034e58495c9/31d5f56b-0ee2-49ae-bd4b-5c54a6ec59ab/c0ry2pc.jpeg)
Transcribed Image Text:**Circle Equation Problem**
**Objective**: Find the standard form of the equation of a circle with the following properties:
- **Center**: \((-9, -7)\)
- **Tangent to the x-axis**
**Task**: Type the standard form of the equation of this circle.
*(Type your equation in the provided answer box.)*
---
**Explanation**:
For a circle tangent to the x-axis, the vertical distance from the center to the x-axis is equal to the radius. Since the center is at \((-9, -7)\), and the y-coordinate is \(-7\), the radius is \(7\).
The standard form of the equation of a circle is:
\[
(x - h)^2 + (y - k)^2 = r^2
\]
Where \( (h, k) \) is the center of the circle and \( r \) is the radius.
For this problem, \( h = -9 \), \( k = -7 \), and \( r = 7 \).
Thus, the standard form of the circle's equation is:
\[
(x + 9)^2 + (y + 7)^2 = 49
\]
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