: +♡ العنوان X= C 15 kN C 1.6 m A simple pin-connected truss is loaded and supported as shown in Figure P1.11. All members of the truss are aluminum pipes that have an outside diameter of 42 mm and a wall thickness of 3.5 mm. Determine the normal stress in each truss member. 30 kN 4.0 m > ۱/۱ Q=5+ 4.5 m Q=S+R9 T Τ M

Please answer the problem completely. Show a free body diagram. Final answers: 1st section: 166.67 mPa 2nd Section: 55.56 mPa 3rd Section: 122.22 mPa

I need to find the forces in each tube but I keep getting stuck. I have been getting really long equations to do algibra onwhich I suspect might be where the error was comming from. The values I have tried are F2 = -0.97786, and -4.889 kips

Q1: A steel pipe column with outside diameter 0.5 in and its wall thickness 0,25 in. supports a load of 4.45 kN. The steel pipe rests on a square steel base plate, this base plate is resting on a concrete slab as illustrated in the attached figure. 1-Determine the bearing stress between the stcel pipe and the stecl plate. 2-If the bearing stress of the steel plate on the concrete slab must be limited to 90 nci what is the minimum allowable plate dimension (a)? 3-Determine the average shear stress in the steel plate, explain? Load Outside diameter - 6.5S in. Wall thickness - 0.25 in. Square steel- base plate Concrete slab

H6.

Solve fast Include fbd. Urgent

A part of the structure for a facory automation system is a beam that spans 30.0 inches as shown below. Loads that are applied at two points each 8.0inches from a support. The left load F1=1800 lb remains constantly applied while the right load F2=1800 lb is applied and removed frequently as the machine cycles. Find the following: Maximum stress Minimum stress Mean stress Alternating stress Stress ratio Solve the missing parameters in complete solution put necessary diagrams if needed. Thanks

Write legibly, provide step by step manual solution, and diagram for below given problem.  An iron rod 6m long and 1.6mm2 in cross section stretches 1.2mm when a mass of 315kg is  hang on it. Compute the modulus of elasticity of the iron.    (Ans. E = 9656.72 Gpa)