airs of parentheses, write a function to generate all combinations of well-formed parentheses. For example, given n = 3, a solution set is: [ "((()))", "(()())", "(())()", "()(())", "()()()" ] """
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| Given n pairs of parentheses, write a function to generate | |
| all combinations of well-formed parentheses. | |
| For example, given n = 3, a solution set is: | |
| [ | |
| "((()))", | |
| "(()())", | |
| "(())()", | |
| "()(())", | |
| "()()()" | |
| ] | |
| """ | |
| def generate_parenthesis_v1(n): | |
| defadd_pair(res, s, left, right): | |
| ifleft==0andright==0: | |
| res.append(s) | |
| return | |
| ifright>0: | |
| add_pair(res, s+")", left, right-1) | |
| ifleft>0: | |
| add_pair(res, s+"(", left-1, right+1) | |
| res= [] | |
| add_pair(res, "", n, 0) | |
| returnres | |
| def generate_parenthesis_v2(n): | |
| defadd_pair(res, s, left, right): | |
| ifleft==0andright==0: | |
| res.append(s) | |
| ifleft>0: | |
| add_pair(res, s+"(", left-1, right) | |
| ifright>0andleft<right: | |
|
add_pair(res, s+")", left, right-1).
|
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- Given an integer array of positive single digit values such as:int a[] = {8,4,2,6,9};1) Write a recursive arrayToN function which returns the concatenation of all array values as an integer value.This function should accept all required data as parameters and return a long integer value.ExamplesIf the array is 8 4 2 6 9 the arrayToN function returns the integer 84269.If the array is 0 2 6 8 9 3 5 1 the arrayToN function returns the integer 2689351.Write a recursive function that finds the minimum value in an ArrayList. Your function signature should be public static int findMinimum(ArrayList<Integer>) One way to think of finding a minimum recursively is to think “the minimum number is either the last element in the ArrayList, or the minimum value in the rest of the ArrayList”. For example, if you have the ArrayList [1, 3, 2, 567, 23, 45, 9], the minimum value in this ArrayList is either 9 or the minimum value in [1, 3, 2, 567, 23, 45] ================================================ import java.util.*; public class RecursiveMin{public static void main(String[] args){Scanner input = new Scanner(System.in);ArrayList<Integer> numbers = new ArrayList<Integer>();while (true){System.out.println("Please enter numbers. Enter -1 to quit: ");int number = input.nextInt();if (number == -1){break;}else {numbers.add(number);}} int minimum = findMinimum(numbers);System.out.println("Minimum: " + minimum);}public static int…Using Javascript Write a higher-order function that when given an array of numbers, return a new array that only includes the even numbers. Hint: filter() function evensOnly(arr) { // your code here}// testconsole.log(evensOnly([3, 5, 6, 8, 2, 11])); /// [6, 8, 2]
- Given an integer array nums, return all the triplets [nums[i], nums[j], nums[k]] such that i != j, i != k, and j != k, and nums[i] + nums[j] + nums[k] == 0. This time, your problem has additional details: Constraints: The solution set must not contain duplicate triplets. The order of the output and the order of the triplets does not matter. 3 <= nums.length <= 3000 -105 <= nums[i] <= 105 Function definition for Java: public List<List<Integer>> threeSum(int[] nums) { // Your code here } Function definition for Python: def threeSum(self, nums: List[int]) -> List[List[int]]: #Your code here Announced Test Cases: Input: nums = [0,1,1] Output: [] Explanation: The only possible triplet does not sum up to 0.Input: nums = [-5,0,5,10,-10,0] Output: [[-10,0,10],[-5,0,5]] Explanation: There are two possible combinations of triplets that satisfy: (-5,0,5) and (-10,0,10). Hint: There are 3 well-known ways to solve this problem!Write a RECURSIVE function, without using any loops, that prints the contents of a matrix with 3 columns. The function should take the matrix and the number of rows as arguments. void print_matrix(int arr[][3], int num_rows);Write a function is ordered that takes an integer array and its size as parameters and returns true if the array elements are ordered in nondecreasing order and returns false if not. For example, integers in {10,0,1,1,5,1009} are ordered in nondecreasing order. On the other hand, integers in {1, 2, 3, 8, 4, 19} are not since 8 > 4
- Programming Language: C Write the following three functions: a) The function gets an array A of length n of ints, and a boolean predicate pred. It returns the smallest index i such that pred(A[i])==true. If no such element is not found, the function returns -1. int find(int* A, int n, bool (*pred)(int)); b) The function gets an array A of length n of ints, and a function f. It applies f to each element of A. void map(int* A, int n, int (*f)(int)); c) The function gets an array A of length n of ints, and a function f. The function f gets 2 ints and works as follows: 1. Start with accumulator = A[0] 2. For i=1...length-1 compute accumulator=f(accumulator, A[i]) 3. Return accumulator For example, if f computes the sum of the two inputs, then reduce() will compute the sum of the entire array. int reduce(int* A, int n, int (*f)(int,int)); Test for the functions: // used for test Q3-find bool is_even(int x) { return x%2 == 0; } bool is_positive(int x) { return x>0; } void…Assume that L is a list of Boolean values, True and False. Write a program in python with a function longestFalse(L) which returns a tuple (start, end) representing the start and end indices of the longest run of False values in L. If there is a tie, then return the first such run. For example, if L is False False True False False False False True True False False 0 1 2 3 4 5 6 7 8 9 10 then the function would return (3, 6), since the longest run of False is from 3 to 6.Write a function that takes two int arrays arr1 and arr2, and their size n as parameters. The functionreturns the number of elements that exist in arr1 and arr2 with indexes i1 and i2 respectively such that i1>=i2.(Example: arr1: [ 1,5,2,3,4,0,7] arr2: [0,1,3,7,4,2] then the function returns 3 ( 0,3,7) )
- Complete the C++ function below: bool CompareArr(int *arr1, int *arr2){ //returns true if both array are equal }Write a function in c programming language that gets an array of points ( function is defined as : typedef struct{ int x; Int y; } point; ) and sorts the array using qsort().Given two points a=(ax,ay) and b=(bx,by) we compare them as follows: 1) if (ax)2+(ay)2 < (bx)2+(by)2, then a should come before b in the sorted array. 2) if (ax)2+(ay)2 = (bx)2+(by)2, then we compare the points by the x coordinate. Remark: For a point a=(ax,ay) the quantity ((ax)2+(ay)2)1⁄2 is the distance of a from the (0,0). That is, we sort the points according to their distance to (0,0), and if for points at the same distance, then we sort them according to the first coordinate. You will need to implement the comparison function, and apply qsort() on the array with this comparison function. For example: - Input: [(3,2), (7,1), (1,1), (3,4), (5,0), (7,1)] - Expected output: [(1,1), (3,2), (3,4), (5,0), (7,1), (7,1) ] Explanation:(1,1) is first because 12+12=2 is the smallest(3,2)…in Python Minima in permutations. Write a program that takes an integer n from the command line, generates a random permutation, prints the permutation, and prints the number of left-to-right minima in the permutation (the number of times an element is the smallest seen so far). Then write a program that takes integers m and n from the command line, generates m random permutations of length n, and prints the average number of left-to-right minima in the permutations generated
