Air is compressed in a two-stage, double acting acting compressor which is electrically driven at 165 rpm. The low pressure cylinder (30.5 x 35.5 cm) receives 6.85 m3/min of air at 96.53 kPaa, 43.3 C, and the high-pressure cylinder (20.3 x 35.5-cm) discharges the air at 717.06 kPaa. Piston rods are 5.1 cm in diameter and the isothermal overall efficiency is 74%. Find a. The volumetric efficiency, % b. The power of the driving motor, kW c. The power savings for two-stage compressor, kW

A turbine is driven by a system that enters the turbine at the ff. conditions: 500 kg/h, 44 atm, 450 deg C, 60 m/s linear speed. The steam exits at a point five meters below the inlet stream of the turbine with the following conditions: atmospheric pressure, 360 m/s speed. 70,000 W of shaft work is delivered by the turbine while 104 kilocalories/h heat is lost. Here are the questions to be answered: 1. Why is the value of Wexp 0? (Explain) 2. Given the above values, can you calculate the Wflow? (Yes/No)

Air (MW=29 g/mol) at 115.00 kPa and 285.00  is compressed steadily to 600.0 kPa. The mass flow rate of the air is 2.00 kg/s and a heat loss of 32.1 kW occurs during the process. You may assume that changes in kinetic and potential energy are negligible, the temperature of the surroundings is 25 ∘C, and that the CP of air is 3.5 R. Given the compressor operates with a second law (reversible) efficiency of 0.60,calculate the following. What is the actual work interaction term in kW? What is the actual exit temperature of the air in Celcius?

For air properties use online source: https://www.peacesoftware.de/einigewerte/luft_e.html  The compressor is operating at steady-state increasing pressure of R-22 refrigerant from 4 bars to 14 bars. Temperature was rising during the process from 12C to 90C. The inlet volumetric flow rate is 1 m3/min and inlet diameter is 0.03m. At the exit the diameter is the same. Heat flow to the surroundings can be neglected. Determine: a.Mass flow rate [kg/s]   SHOW AND EXPLAIN ALL STEPS PLEASE thanks