Advanced Engineering Mathematics
10th Edition
ISBN: 9780470458365
Author: Erwin Kreyszig
Publisher: Wiley, John & Sons, Incorporated
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Question
5
![hisa Isnogcib sei d
wod2.isnogsib
oldim
1. A =
A =
Siga eriti
2. A =
A =
2.5 EXERCISES
vities
In Exercises 1-6, solve the equation Ax = b by using the LU
factorization given for A. In Exercises 1 and 2, also solve Ax = b
by ordinary row reduction. $1 ei tuqni ar
HER
-3 5
42
obsl
100
-1 1 0
owl smid
2 -5 1
1
-1
3 -7 -2
1812151
1
own gat
6 -4
7130
2
2
3. A = -6
8
gies C
4 3 -5
-4 -5 7
8
6-8
].
0
1
0
-1
0
0
-1
qqu
ill:
18
2017 ind
, b =
5
2
b= =
i][
0
L
3-71-27
0 -2 -1
UE 2nist
0 -
4
Find an LU factorization of A =
PRACTICE PROBLEM
0-2
0
has only three pivot columns, so the method of Example 2 will produce only the first
three columns of L. The remaining two columns of L come from 15.]
-4
6
27
3 -5
2
2
2
-2 ,b= 0
5
0
wo
od2
TO PRACTICE'R
and world 80
donnos on
231 odi
istenen szorlw
olugmo) ce
(15) d
LI to
2-4-2 3
6-9 -5 8
2 -7 -3 9
4 -2 -2 -1
-6 3 3 4
Aankope
of bodromid,
madinggis diqqA) sai
A =
-3
4 -1
4
(Paloviqtoris
LOA
A =
5. A =
YAM
ed as A VW
airT)
A =
2000 SAJTAM, ald
esiuns 0132d-2
4
4. A = 1-31 1, b =
=
33007 5
0
1 0
I
1
A gnizo,TI
[Note: It will turn out that A
1
bet indien UST
0 0 0
1/2 1
3/2
2
16
0
-5 1
mo (or
8
2 -1 27
Alo 199
-3 4
0
of bon
0
01
100
210
-1 0
1
-4 3 -5
1
2 -7 -7 -6
-1 26
4
8
-4 -1 9
01
-Abai7 81
0715wolsed kl 01
-52 Ianogsib and no
7 pH) aslugnain
ainsinsoslag worvino
-2
snrw mizo,alA
4
ogneria
U=AMI .00
bsouber wor
ban A
quod
moitos2 to
-2-1
0-6
0 0
-2 -4 -3 adw to los
191
7
0
3
On ai sevib
0 1
0
0
0
0
0
,b=
A paoqqu2.15
sanaupos
Do A
-2 -4 -3
-3 1
0 2
0
0
0
1
1](https://content.bartleby.com/qna-images/question/fb1de760-1ce0-4628-8acb-05cd78cc2c48/63f305a2-ac3e-4a48-a724-1e41597b7a1c/94fkvgp_processed.jpeg)
Transcribed Image Text:hisa Isnogcib sei d
wod2.isnogsib
oldim
1. A =
A =
Siga eriti
2. A =
A =
2.5 EXERCISES
vities
In Exercises 1-6, solve the equation Ax = b by using the LU
factorization given for A. In Exercises 1 and 2, also solve Ax = b
by ordinary row reduction. $1 ei tuqni ar
HER
-3 5
42
obsl
100
-1 1 0
owl smid
2 -5 1
1
-1
3 -7 -2
1812151
1
own gat
6 -4
7130
2
2
3. A = -6
8
gies C
4 3 -5
-4 -5 7
8
6-8
].
0
1
0
-1
0
0
-1
qqu
ill:
18
2017 ind
, b =
5
2
b= =
i][
0
L
3-71-27
0 -2 -1
UE 2nist
0 -
4
Find an LU factorization of A =
PRACTICE PROBLEM
0-2
0
has only three pivot columns, so the method of Example 2 will produce only the first
three columns of L. The remaining two columns of L come from 15.]
-4
6
27
3 -5
2
2
2
-2 ,b= 0
5
0
wo
od2
TO PRACTICE'R
and world 80
donnos on
231 odi
istenen szorlw
olugmo) ce
(15) d
LI to
2-4-2 3
6-9 -5 8
2 -7 -3 9
4 -2 -2 -1
-6 3 3 4
Aankope
of bodromid,
madinggis diqqA) sai
A =
-3
4 -1
4
(Paloviqtoris
LOA
A =
5. A =
YAM
ed as A VW
airT)
A =
2000 SAJTAM, ald
esiuns 0132d-2
4
4. A = 1-31 1, b =
=
33007 5
0
1 0
I
1
A gnizo,TI
[Note: It will turn out that A
1
bet indien UST
0 0 0
1/2 1
3/2
2
16
0
-5 1
mo (or
8
2 -1 27
Alo 199
-3 4
0
of bon
0
01
100
210
-1 0
1
-4 3 -5
1
2 -7 -7 -6
-1 26
4
8
-4 -1 9
01
-Abai7 81
0715wolsed kl 01
-52 Ianogsib and no
7 pH) aslugnain
ainsinsoslag worvino
-2
snrw mizo,alA
4
ogneria
U=AMI .00
bsouber wor
ban A
quod
moitos2 to
-2-1
0-6
0 0
-2 -4 -3 adw to los
191
7
0
3
On ai sevib
0 1
0
0
0
0
0
,b=
A paoqqu2.15
sanaupos
Do A
-2 -4 -3
-3 1
0 2
0
0
0
1
1
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