erOthe questions below05.50 147-AH"=-276.6 kJAH = -827.5 kJAH* = -296.9 kJte in internal energy for the reaction, in0AH = -276.6 kJΔΗ° = -827.5 kJAH = -296.9 kJUse the following reaction information to solve the questions below1. OF, (g) + H₂O (1)--> O₂(g) + 2HF (g)2. SF, (8) + 2H₂O (1)--> 4HF (8) + SO₂ (g)3. S(s) + O₂ (B)--> SO₂ (g)Q1. Determine AH (in kJ) at 298 K for the following reaction:20F₂ (g)+2S (s)--> SO₂(g) + SF₂ (g)ΔΗ° = ???Q2. From reaction 1, if the reactants react completely, and the total pressure after thereaction completes is 0.99 atm, what is the partial pressure of O₂, in atm?Q3. From reaction 2, at 25 °C, what is the change in internal energy for the reaction, in kJ?Q4. If 42.0 g of sulfur, S, is dropped into 42.0 g of water, where the sulfur started at 68.0"C and the water started at 15.0 °C, what is the final temperature of the water, in °C?Melting point of sulfur is 112.8 °C, for water: CH20) = 4.184 J/g °C), for S: Cps(s) = 22.75J/mol °C)Bonus. From reaction 3, if the reactants reacts completely in an 85.0 L container andreleases 4203 kJ of energy at 298 K, what is the total pressure of SO₂(g) (in atm) afterreaction?EvNO SMOKING

The thermochemical equations can be treated as algebraic equation which can be added, subtracted, multiplied or divided. i.e. If the coefficient of the substances are multiplied or divided by some number then the value of ∆H is multiplied or divided by the same number. If the reaction is reversed then the sign of ∆H changes but the magnitude remains the same.Answer of question no. 1) is -319.5 KJ NOTE : Dear student since you have posted multiple questions we will solve only first question for you if you want other questions to be solved then kindly post them separately.