agrams for the beam shown below. 10 kN p= 20 kN/m

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A continuous beam is loaded as shown     1. Which of the following gives the fixed end moment AB in kN-m?  a. 12 kN-m b. 8 kN-m c. 10 kN-m d. 5 kN-m 2. Which of the following gives the distribution factor at B for the member BA in %?  a. 33.3% b. 66.6% c. 35.47% d. 45% 3. Which of the following nearly gives the moment at B using moment distribution method in kN.m?  a. 12.89 b. 13.2 c. 11.2 d. 14.6

In the system shown in the figure, parts AB, BC and CD are of equal length and 4 m. Clockwise from point AA moment of 10 kNm is applied in the opposite direction. The distributed load of 3 kN/m at BC is upward. Beam DA load of 5 kN was applied downwards from the point. The profile of the beam has a 100 mm edge as seen on the right side.was formed by subtracting a circle with a diameter of 80 mm from the center of a regular hexagon of length. Accordingly; A)Calculate the reaction forces at B and C B)Draw shear force and bending moment diagrams C)Calculate the maximum bending and show it on the bending moment diagram. D)Calculate the sectional moment of inertia of the profile E)Calculate the maximum stress in the beam NOTE:For option C, you need to obtain a parobolic expression when drawing the bending moment diagram. You need to use derivation.

1. Determine the maximum deflection of the steel beam shown in Figure 1. E = 200 GPa and I = 60(10°) mm“. 8 kN -9 m– -3 m- 2 kN 6 kN Figure 1

A simply supported beam supports the applied loads as shown. If E = 200 GPa and I = 0.0015 m4. Using double integration method, Determine the maximum delection along span AB only.