Again assume each channel of our power supply can provide 30 V and we want to run a 60 V hair dryer motor. So, we again put the two channels in series for double the voltage. But, if you try this with a non-isolated supply, bad things will happen. Don't do that. The following depicts a circuit where internally the supplies have a common ground (i.e., they are not isolated). Non-Isolated Power Supply Droop2 www 1mQ Channel2 30V 3.3A max Channel1 30V 3.3A max I 1 Droop1 I ww 1mQ Red 1 I I 1 Black Red Black JumperCable 26m0 15A max Motor 1200 Needs -60V (a) Show that the current through the jumper cable will greatly exceed its current rating (which, as shown in the schematic, is 15 A). If this happens for more than a very short time, it will melt. (b) Show that the current through Channell greatly exceeds its maximum current rating. If the short circuit protection circuitry doesnt activate quickly, you will fry your power supply. Hint: You can redraw the circuit in a manner similar to what we have seen in a couple of other instances where it appears parts of the circuit are mostly, but not completely, decoupled from each other.

Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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4. Again assume each channel of our power supply can provide 30 V and we want to run a
60 V hair dryer motor. So, we again put the two channels in series for double the voltage.
But, if you try this with a non-isolated supply, bad things will happen. Don't do that. The
following depicts a circuit where internally the supplies have a common ground (i.e., they
are not isolated).
Non-Isolated Power Supply
Droop2
ww
1mQ
Channel2
30V
3.3A max
Channel1
30V
3.3A max
Droop1
1mQ
I
I
I
1
I
Red
1
I
1
Black
Red
Black
JumperCable
26mQ
15A max
Motor
1200
Needs -60V
(a) Show that the current through the jumper cable will greatly exceed its current rating
(which, as shown in the schematic, is 15 A). If this happens for more than a very short
time, it will melt.
(b) Show that the current through Channell greatly exceeds its maximum current rating.
If the short circuit protection circuitry doesnt activate quickly, you will fry your power
supply.
Hint: You can redraw the circuit in a manner similar to what we have seen in a couple of
other instances where it appears parts of the circuit are mostly, but not completely, decoupled
from each other.
Transcribed Image Text:4. Again assume each channel of our power supply can provide 30 V and we want to run a 60 V hair dryer motor. So, we again put the two channels in series for double the voltage. But, if you try this with a non-isolated supply, bad things will happen. Don't do that. The following depicts a circuit where internally the supplies have a common ground (i.e., they are not isolated). Non-Isolated Power Supply Droop2 ww 1mQ Channel2 30V 3.3A max Channel1 30V 3.3A max Droop1 1mQ I I I 1 I Red 1 I 1 Black Red Black JumperCable 26mQ 15A max Motor 1200 Needs -60V (a) Show that the current through the jumper cable will greatly exceed its current rating (which, as shown in the schematic, is 15 A). If this happens for more than a very short time, it will melt. (b) Show that the current through Channell greatly exceeds its maximum current rating. If the short circuit protection circuitry doesnt activate quickly, you will fry your power supply. Hint: You can redraw the circuit in a manner similar to what we have seen in a couple of other instances where it appears parts of the circuit are mostly, but not completely, decoupled from each other.
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