After connecting a 4.71µF capacitor to an AC-RLC circuit with a constant voltage amplitude, you get the following (frequency , current) pairs, (f in Hz, I in mA) = (200.0 , 6.62) , (250.0 , 8.66), (300.0, 10.95) , (350.0 , 13.46), (400.0 , 16.04), (450.0, 18.36), (500.0, 19.96), (550.0 , 20.50), (600.0 , 20.05) , (650.0, 18.95), (700.0 , 17.59), (750.0, 16.21) , (800.0 , 14.92). What is the inductance of the

After connecting a 4.71µF capacitor to an AC-RLC circuit with a constant voltage amplitude, you get the following (frequency , current) pairs, (f in Hz, I in mA) = (200.0 , 6.62) , (250.0 , 8.66), (300.0, 10.95) , (350.0 , 13.46), (400.0 , 16.04), (450.0, 18.36), (500.0, 19.96), (550.0 , 20.50), (600.0 , 20.05) , (650.0, 18.95), (700.0 , 17.59), (750.0, 16.21) , (800.0 , 14.92). What is the inductance of the

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

See similar textbooks

Similar questions

The capacitor is short circuited when carrying out ac small signal analysis. True False
if this is an rl circuit, how do we find the current in the inductor? or how do we analyze this circuit for transient analysis?
In the compuntation of experimental time constant of an RC circuit in the charging phase, explain the reason why we should not directly plot the capacitor voltage as a function of time in solving?
A 20ohms resistor is connected in series with an inductor, a capacitor and an ammeter across a 25V variable frequency supply. When the frequency is 400Hz the current is at the maximum value of 0.5A and the p.d. across the capacitor is 150V. Calculate the capacitance of the capacitor and the resistance and inductance of the inductor.
For a series RLC circuit with a sinusoidal input voltage, the amplitude of the current passing through the circuit (I, in mA) is plotted as a function of frequency for two cases: Curve 1 with R1, L1. and Curve 2 with R2. L2 as shown in the next figure. The value of the capacitor used in the circuits is C=0.01 micro Farads. If the value of R2 =1600 Ohm then the input voltage (in volts) is: 7.5 25 110 Frequency H2 O a. 4 O b. 16 sin(9888 t) O c. 8 O d. 8 cos(6.28 f t) O e. 8 sin (6.28 R t)
The graph shows the current vs. frequency graph of FOUR (4) RLC series circuits with different combinations of resistance (R) and capacitance (C) values. The value of L and the peak-to-peak voltage across both sets of data are the same. Find the following quantities:
Q6. Figure Q6 shows a modulated waveform v(t) in microvolts as a function of time t in nanoseconds. 25 50 75 100 125 150 175 200 225 250 50 40 40 30 30 20 20 10 10 -10 -10 -20 -20 -30 -30 -40 -40 -50 -50 250 25 50 75 100 125 150 175 200 225 time/ns Figure Q6: Modulated waveform (a) Describe the modulation scheme. (b) What are the values of the carrier frequency and the modulation frequency? (c) What is the value of the modulation index? (d) What is the transmission efficiency (ratio of modulated to total power) in this example? (e) Sketch the spectrum of this modulated waveform indicating the relative magnitudes of the various spectral components. (f) The modulating wave in this example is substituted with a square wave of 50% duty cycle and of fundamental frequency 1.0 MHz. Sketch the absolute value of the spec- trum of the modulated waveform indicating the frequencies and relative magnitudes of the sideband components. (g) Demodulation of this type of signal is usually accomplished…
Capacitance by AC- Bridge: The impedance of the capacitor of capacitance C is: Select one: a. Directly proportional to 1/C b. Directly proportional to 1/C2 C. Directly proportional to C2 d. Inversely proportional to 1/C
The voltage applied to the 622mH inductor is given by v(t)= 15e5t volt and IL (0)=0. Calculate the current. Select one: O a. 14.15[1-es O b. 4.82[1-e5t] O c. 8.57[1-e5t] O d. 20[1-e5t]
Shown in the figure below is an "RLC" circuit driven by an AC power source. The AC power source has an RMS voltage of Vps(RMS) = 11.80 Volts and is running at a frequency of f = 147000 Hz. The resistor has a resistance of R = 3910 Ω, the capacitor has a capacitance of C = 4.01e-10 Farads, and the inductor has an inductance of L = 5.97e-03 Henries.Write the FORMULA for the total impedance of the circuit Ztot = Write the FORMULA for the phase of the total impedance of the circuit ?Ztot = Determine the numerical value of Ztot = ΩDetermine the numerical value of ?Ztot = degreesDetermine the current through the circuit: I(PEAK) = Amps I(RMS) = Amps Determine the voltage across the inductor: VL(PEAK) = Volts VL(RMS) = Volts Determine the voltage across the capacitor: VC(PEAK) = Volts VC(RMS) = Volts If a second circuit were connected in parallel with the resistor, this circuit would be considered as: a high-pass filtera flux capacitor a radio tunera phase…
Solve for the current going through each passive component and the voltage at the capacitor.
7. In DC analysis all capacitors are replaced by a short circuit equivalent and in AC as an open circuit. Select one:TrueFalse 8. En el análisis AC del BJT todas las fuentes de cd se hacen igual a cero y las reemplaza una conexión de cortocircuito a tierra. Seleccione una: Verdadero Falso 9. The superposition theorem is applicable to the analysis and design of the dc and ac components of a BJT network, allowing the analysis of the system's dc and ac responses to be separated. Select one:TrueFalse 10. An equivalent model is a combination of appropriately selected circuit elements that accurately simulates the real behavior of a semiconductor device in any operating condition. Select one:TrueFalse