After a fall, a 71 kg rock climber finds himself dangling from the end of a rope that had been 18 m long and 10 mm in diameter but has stretched by 2.2 cm. For the rope, calculate (a) the strain, (b) the stress, and (c) the Young's modulus. (a) Number i Units (b) Number i Units (c) Number i Units

After a fall, a 71 kg rock climber finds himself dangling from the end of a rope that had been 18 m long and 10 mm in diameter but has stretched by 2.2 cm. For the rope, calculate (a) the strain, (b) the stress, and (c) the Young's modulus. (a) Number i Units (b) Number i Units (c) Number i Units

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Related questions

Q: During a wrestling match, a 116 kg wrestler briefly stands on one hand during a maneuver designed to…

A: Basic Details The young’s modulus is defined as the ratio of stress to that of strain. Stress is…

Q: An 9.63-kg stone at the end of a steel (Young's modulus 2.0 x 1011 N/m²) wire is being whirled in a…

A: The strain in the wire is strain=LΔL=2.43×10−4Explanation:Step 1: Given- The mass of the stone is…

Q: A brass wire (E = 100 x 10° Nm2) which is 6.336 m long experienced an elongation of 1.21 mm by a…

A: Given, Young's modulus, E=100×109Nm2 Length, L=6.336m Elongation, ∆L=1.21×10-3m Mass, m=29kg a.…

Q: A 45 kg boy whose leg bones are 5 cm² in area and 50 cm long falls through a height of 2 m without…

Q: After a fall, a 85 kg rock climber finds himself dangling from the end of a rope that had been 18 m…

A: Given Data Mass of the rock climber is m=85 kg Length of the rope is l=18 m Diameter of the rope is…

Q: After a fall, a 97 kg rock climber finds himself dangling from the end of a rope that had been 16 m…

Q: After a fall, a 84 kg rock climber finds himself dangling from the end of a rope that had been 13 m…

Q: After a fall, a 97 kg rock climber finds himself dangling from the end of a rope that had been 16 m…

A: Given, Mass of Climber (M) = 97 kg. Initial Length of Rope (L) = 16 meter.…

Q: After a fall, a 71 kg rock climber finds himself dangling from the end of a rope that had been 15 m…

Q: After a fall, a 97 kg rock climber finds himself dangling from the end of a rope that had been 16 m…

A: Given data- Mass of rck climber m=97 kg Rope length L=16 m Diameter D=9.4 mm, radius r=4.7×10-3 m…

Q: After a fall, a 89 kg rock climber finds himself dangling from the end of a rope that had been 12 m…

Q: After a fall, a 87 kg rock climber finds himself dangling from the end of a rope that had been 17 m…

Q: After a fall, a 73 kg rock climber finds himself dangling from the end of a rope that had been 16 m…

Q: After a fall, a 87 kg rock climber finds himself dangling from the end of a rope that had been 14 m…

Q: After a fall, a 72 kg rock climber finds himself dangling from the end of a rope that had been 15 m…

Q: After a fall, a 73 kg rock climber finds himself dangling from the end of a rope that had been 13 m…

Q: answer should be in decimal. (Li

A: Givenm=86 kgL=16 md=7.8 mm=7.8×10-3 m∆L=2.0 cm=2×10-2 m

Q: After a fall, a 70 kg rock climber finds himself dangling from the end of a rope that had been 14 m…

A: Solution: (a). The strain is given by the ratio of change in length to the original length of the…

Q: A particular human hair has a Young's modulus of 3.31 x 10° N/m2 and a diameter of 145 um. If a 236…

Q: After a fall, a 97 kg rock climber finds himself dangling from the end of a rope that had been 16 m…

A: Length of the rope, L = 16 m = 16 x 102 cm Change in length of the rope, ∆L = 3.3 cm Strain is…

Q: An 9.85-kg stone at the end of a steel (Young's modulus 2.0 x 10 N/m²) wire is being whirled in a…

A: We have the Young's modulus Y=stressstrain

Q: Young's modulus

Q: After a fall, a 88 kg rock climber finds himself dangling from the end of a rope that had been 14 m…

Q: The figure shows the stress-strain curve for a material. The scale of the stress axis is set by s =…

Q: You hang a 30 kg mass from the end of a rod that is 12 m by 2 mm by 2 mm. You observe that the rod's…

A: To solve this problem, we need to use the concepts of stress and strain. Stress is defined as the…

Q: After a fall, a 84 kg rock climber finds himself dangling from the end of a rope that had been 13 m…

Q: During a wrestling match, a 119 kg wrestler briefly stands on one hand during a maneuver designed to…

Q: After a fall, a 86 kg rock climber finds himself dangling from the end of a rope that had been 16 m…

Q: Let A be the last digit and let B be the second to last digit of your 8-digit student ID. A steel…

A: Mass of object = 139.8 kgExplanation:

Q: After a fall, a 100 kg rock climber finds himself dangling from the end of a rope that had been 13 m…

Q: After a fall, a 75 kg rock climber finds himself dangling from the end of a rope that had been 14 m…

Q: After a fall, a 94 kg rock climber finds himself dangling from the end of arope that had been 19 m…

A: Given value--- mass = 93 kg. initial length = 19 m. initial diameter = 8.4 mm. Change in length =…

Q: After a fall, a 80 kg rock climber finds himself dangling from the end of a rope that had been 14m…

Q: After a fall, a 90 kg rock climber finds himself dangling from the end of a rope that had been 16 m…

A: Part (a) extension or change in length= 3.3cm = 0.033 m length = 16m Strain = change in length ÷…

Q: stretched by 3.3 cm. For the rope, calculate (a) the strain, (b) the stress, and (c) the Young's…

Q: After a fall, a 84 kg rock climber finds himself dangling from the end of a rope that had been 13 m…

Concept explainers

Mechanical Properties of Solids

There are three types of matter- solid, liquid and gas. Out of them, solids have a rigid shaped and size. The intermolecular forces of attractions in solids are greatest. Mechanical properties are the physical properties of a material which it shows, when it is provided with certain amount of force or load. These properties are to be kept in mind for various purposes. When a force is applied to an object, the object may or may not get deformed depending upon its elastic property. But every time the object develops a restoring force against the force applied. This is commonly known as stress. If the object changes its dimensions due to the force applied it develops strain ( which is the ratio of change in dimension to the original dimension).

Question

After a fall, a 71 kg rock climber finds himself dangling from the end of a rope that had been 18 m long and 10 mm in diameter but has
stretched by 2.2 cm. For the rope, calculate (a) the strain, (b) the stress, and (c) the Young's modulus.
(a) Number
i
Units
(b) Number
i
Units
(c) Number
i
Units

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2: Calculation of the strain

VIEW

Step 3 : Calculation of stress

VIEW

Step 4: calculation of young's modulus

VIEW

Step 5 : conclusion

VIEW

Step by step

Solved in 5 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions

After a fall, a 88 kg rock climber finds himself dangling from the end of a rope that had been 12 m long and 8.2 mm in diameter but has stretched by 2.6 cm. For the rope, calculate (a) the strain, (b) the stress, and (c) the Young's modulus. (a) Number i Units (b) Number i Units (c) Number i Units
Question 4 of 7 > A particular human hair has a Young's modulus of 3.64 × 10° N/m² and a diameter of 148 μm. If a 217 g object is suspended by the single strand of hair that is originally 15.5 cm long, by how much AL hair will the hair stretch? If the same object were hung from an aluminum wire of the same dimensions as the hair, by how much ALAI would the aluminum stretch? If the strand of hair is modeled as a spring, what is its spring constant khair? AL hair ALAI = Khair = m N/m Question Source: Freedman College Physics 3e | Publisher: Mac
After a fall, a 99 kg rock climber finds himself dangling from the end of a rope that had been 14 m long and 11 mm in diameter but has stretched by 2.1 cm. For the rope, calculate (a) the strain, (b) the stress, and (c) the Young's modulus. (a) Number i Units (b) Number i Units (c) Number i Units > > >
A steel cable of diameter 2 cm is acted upon by 50000 N of tension. If Young’s modulus is 20 x 1010 N/m2 and its unstressed length was 5 m, what is its length while stressed? A 4 mm B 5 m C 5 m 1 mm D 5 m 4 mm
When pushing off of a pool wall, a swimmer exerts a force parallel to the length of her femur, compressing it 3 × 10−5 m. The bone is equivalent to a uniform cylinder 36.0 cm long and 1.75 cm in radius. Young's modulus for bone is 16 × 10⁹ N/m². (a) Calculate the force exerted (in N). 1710 X Consider the basic definition for Young's modulus. N (b) If her mass is 65.5 kg and water resistance is negligible, what is her acceleration (in m/s²)? Assume her weight is precisely supported by the water. m/s² (c) How fast (in m/s) is she going once she exerts this force through a distance of 20.5 cm, starting from rest? m/s
A rope of length 40.0 meters and 5.0 mm in diameter elongates by 1.0 meters when supporting a 50.0 kilogram mountain climber. What is the Stress and strain experienced by the rope?
answer in whole number, scientific notation is not allowed
A 5.0 x 102 N object is hung from the end of a wire of cross-sectional area 1x106 cm?. The wire stretches from its original length of 200.00 cm to 200.50 cm. What is the stress on the wire? A 5.0 x 10^8 N/m2 (B) 1.0 x 10^8 N/m2 (c) 5.0 x 102 N/m² D 1.0 x 10^6 N/m2
A child slides across a floor in a pair of rubber-soled shoes. The frictional force acting on each foot is 20.0 N. The footprint area of each shoe sole is 11.0 cm, and the thickness of each sole is 5.80 mm. Find the horizontal distance by which the upper and lower surfaces of each sole are offset. The shear modulus of the rubber is 3.00 x 10 N/m2. Your response differs significantily from the correct answer. Rework your solution from the beginning and check each step carefully. mm Need Help?Read i
After a fall, a 74 kg rock climber finds himself dangling from the end of a rope that had been 15 m long and 9.8 mm in diameter but has stretched by 2.4 cm. For the rope, calculate (a) the strain, (b) the stress, and (c) the Young's modulus. (a) Number Units (b) Number i Units (c) Number Units
Consider a square-faced beam supporting a section of a building. a) Before installation, the length of the beam is found to be l0 = 15.02 m (figure a). After installation and construction, the length is remeasured and found to be l = 14.98 m (figure b). Determine Young's Modulus Y in N/m2 for the beam if it supports a mass m = 35000 kg and has a side length d = 1.9 m. b) Suppose that after the beam is installed it needs to be repaired. The weight it supports is removed and replaced with a new mass m2 (figure c). After the new mass is supported, the side length is remeasured and found to be larger with a difference of Δd. Assuming that this side length deformation is uniform and small, write an expression for determining Poisson's ratio v for this beam if its Young's modulus Y is known.
After a fall, a 85 kg rock climber finds himself dangling from the end of a rope that had been 14 m long and 8.6 mm in diameter but has stretched by 2.5 cm. For the rope, calculate (a) the strain, (b) the stress, and (c) the Young's modulus. (a) Number i Units (b) Number i Units (c) Number i Units