Adult men have heights with a mean of 69.0 inches and a standard deviation of 2.8 inches. Find the z-score of a man 59.4 inches tall. (to 2 decimal places)

A student graduated from a 4 -year college with an outstanding loan of $9563 where the average debt is $8558 with a standard deviation of $1860 . Another student graduated from a university with an outstanding loan of $12,370 where the average of the outstanding loans was $10,318 with a standard deviation of $2144 Find the corresponding z score for each student. Round z scores to two decimal places.   College student:     =z   University student: =z

The body temperatures of adults are normally distributed with a mean of 98.6° F and a standard deviation of 0.27° F. What temperature represents the 95th percentile? Click to view page 1 of the table. Click to view page 2 of the table. OA. 99.04° F OB. 98.95° F OC. 98.16° F O D. 99.13° F C

The heights of women follow a normal distribution with a mean height of 63.7, and a standard deviation in height of 2.9 in.  What height separates the tallest 10% of women from the rest.  Round your result to 1 decimal place.