add the cectors ANALYTICALLY for the Gven 1, 2, and 3. and please show your work with encoded solutions and follow the  images for the format of answers. A swimmer in Pandacan swims 10 m East and then turns North and      swims 15 m. Calculate the total displacement of the swimmer. 2.  Pedro, a fisherman from Zambales catches fishes at the Island, using his motorized boat he travels 60 m East, then turns 45 m North and      finally travels 30 m West. What is the total displacement of Pedro?   3. A boatman at Manila Bay leaves the wharf and travels 10 m East then continue moving 10 m North. Determine the boatman’s resultant  displacement.

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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add the cectors ANALYTICALLY for the Gven 1, 2, and 3. and please show your work with encoded solutions and follow the  images for the format of answers.

  1. A swimmer in Pandacan swims 10 m East and then turns North and      swims 15 m. Calculate the total displacement of the swimmer.

2.  Pedro, a fisherman from Zambales catches fishes at the Island, using his motorized boat he travels 60 m East, then turns 45 m North and      finally travels 30 m West. What is the total displacement of Pedro?

 

3. A boatman at Manila Bay leaves the wharf and travels 10 m East then continue moving 10 m North. Determine the boatman’s resultant  displacement. 

Sample Problem: Find the resultant force and direction of these two forces
acted on the box, F1 is 6 Newtons East and F2 is 5 Newtons North.
Solutions:
c2 = a² + b²
5 N
= 0.83
tan 0
opposite side
c2 = (6N)² + (5N)²
c2 = 36N? + 25N?
adjacent side 6 N
e = tan-1 = 39.69° or 40°
%3D
c2 = 61N?
c = 7.81 N
Resultant force (FR) = 7.81 N, 40°N of E
Transcribed Image Text:Sample Problem: Find the resultant force and direction of these two forces acted on the box, F1 is 6 Newtons East and F2 is 5 Newtons North. Solutions: c2 = a² + b² 5 N = 0.83 tan 0 opposite side c2 = (6N)² + (5N)² c2 = 36N? + 25N? adjacent side 6 N e = tan-1 = 39.69° or 40° %3D c2 = 61N? c = 7.81 N Resultant force (FR) = 7.81 N, 40°N of E
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