Add curved arrow(s) to draw step 1 of the mechanism. Modify the given drawing of the product as needed to show the intermediate that is formed in this step. Use the +/- tools to add/remove charges, and use the single bond tool to interconvert between double and single bonds.

Part A Draw a reasonable mechanism for this reaction. Interactive 3D display mode Ph Ph -P=CH, CH2 Ph Edit the reaction by drawing all steps in the appropriate boxes and connecting them with reaction arrows. Add charges where needed. Electron flow arrows should start on an atom or a bond and should end on an atom, bond, or location where a new bond should be created. D 5 C Q Q Q H x" iim H CI Br P F P Pearson

Curved arrows are used to illustrate the flow of electrons. Using the provided starting structure, draw the curved electron- pushing arrows for the following reaction or mechanistic steps. Be sure to account for all bond-breaking and bond-making steps. Then draw any missing organic intermediates or products for this reaction. Include all lone pairs in the structures. Ignore inorganic byproducts, counterions, and solvents. H in Select to Add Arrows HCI > Please select a drawing or reagent from the question area

Add the missing nucleophile to the substitution reaction in the drawing area below. Note for advanced students; You can assume the correct solvent conditions are used in this reaction. III... + X 5 IIIII ... OH

Curved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction or mechanistic step(s). Be sure to account for all bond-breaking and bond-making steps.

027 In Part 1 add the curved arrows to the nucleophilic acyl substitution reaction mechanism. In Part 2, answer the multiple-choice question about the reaction in Part 1. Part 1 4 See Periodic Table O See Hint :0: :Br: Add the missing curved arrow notation. S CI Br Part 2 Which statement is most correct regarding the equilibrium for the above reaction? Choose one: O The equilibrium favors the right (i.e., Kea > 1) because acetate is a better leaving group than bromide. O The equilibrium favors the right (i.e., Kea > 1) because bromide is a better leaving group than acetate. O The equilibrium favors the left (i.e., Keq« 1) because acetate is a better leaving group than bromide. O The equilibrium favors the left (i.e., Keg 1) because bromide is a better leaving group than acetate. +

Need help, please box answer!

Clearly label the energy diagram below when answering each part. If there is more than one specific type of label, give an appropriate number afterwards (i.e. Int. 1, Int. 2, etc). State how many step(s) are in the overall reaction, if more than one, clearly label where they start and end Identify the rate determining step (rds) Label all transition state(s) (TS) Label all intermediate(s) (Int.) Label all activation energy(ies) (Ea) Label the heat of the reaction (ΔH) State whether the overall reaction is endothermic or exothermic. please explaing each step. Thank you.