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Activity: Problem Solving. Read and analyze the given problem then answer the following questions. 1. A random sample of n = 90 is taken from a normally distributed population with a mean of µ = 80 and standard

Activity: Problem Solving. Read and analyze the given problem then answer the following questions. 1. A random sample of n = 90 is taken from a normally distributed population with a mean of µ = 80 and standard

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Activity: Problem Solving. Read and analyze the given problem then answer the following questions. 1. A random sample of n = 90 is taken from a normally distributed population with a mean of u = 80 and standard deviation of o = 5. Given the sample mean and standard deviation of x = 77 and s = 3.3 respectively. Solve for test statistic. Given: Solution: Ho = 2. A student assistant administers an exam for the incoming grade 11 ABM students. Fifteen incoming grade 11 ABM students were selected randomly, and the results were as follows mean score of 90 with standard deviation of 10. The population parameters are u = 83 and o = 15. Given: Solution: Ho = n = x=
Transcribed Image Text:Activity: Problem Solving. Read and analyze the given problem then answer the following questions. 1. A random sample of n = 90 is taken from a normally distributed population with a mean of u = 80 and standard deviation of o = 5. Given the sample mean and standard deviation of x = 77 and s = 3.3 respectively. Solve for test statistic. Given: Solution: Ho = 2. A student assistant administers an exam for the incoming grade 11 ABM students. Fifteen incoming grade 11 ABM students were selected randomly, and the results were as follows mean score of 90 with standard deviation of 10. The population parameters are u = 83 and o = 15. Given: Solution: Ho = n = x=
Illustrative Example 1: Solve for the test statistic. The heart rates of 50 patients in an ICU have mean 95.3 beats/min and standard deviation 16.9 beats/min. Are heart rates from ICU patients unusual given normal heart rate has mean of 72 beats/min with a significance of 0.01? Given: Solution: - normal heart rate - number of patients being surveyed *The sample size of 50 patients is large enough for the Central Limit Theorem to satisfy the assumption that the sampling distribution of means Ho = 72 beats/min. n= 50 patients the appropriate test statistic to use is z-test, since the distribution is normal, we can use s as an estimator of o. - substitute all the give (95.3 -72) (16.9//50) is normal. - heart rate of 50 patients - therefore we will be using x= 95.3beats/min. z = 9.75 - test statistic o = unknown * Central limit theorem states that for a sample which is large enough the value of t – test is approximately equal to the value of z – test as the sample size increases. In z-test s= 16.9 beats/min. - sample standard deviation - significance level *this will be essential on our next topic. a = 0.01 this case we can use s as an estimator of o.
Transcribed Image Text:Illustrative Example 1: Solve for the test statistic. The heart rates of 50 patients in an ICU have mean 95.3 beats/min and standard deviation 16.9 beats/min. Are heart rates from ICU patients unusual given normal heart rate has mean of 72 beats/min with a significance of 0.01? Given: Solution: - normal heart rate - number of patients being surveyed *The sample size of 50 patients is large enough for the Central Limit Theorem to satisfy the assumption that the sampling distribution of means Ho = 72 beats/min. n= 50 patients the appropriate test statistic to use is z-test, since the distribution is normal, we can use s as an estimator of o. - substitute all the give (95.3 -72) (16.9//50) is normal. - heart rate of 50 patients - therefore we will be using x= 95.3beats/min. z = 9.75 - test statistic o = unknown * Central limit theorem states that for a sample which is large enough the value of t – test is approximately equal to the value of z – test as the sample size increases. In z-test s= 16.9 beats/min. - sample standard deviation - significance level *this will be essential on our next topic. a = 0.01 this case we can use s as an estimator of o.
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