Activity 3: Can you prove it? A. Directions: Use indirect proof to prove the scenario. Given: A is not the midpoint of segment MN. Prove: MA # AN B. Directions: Using paragraph form, write the direct proof of the scenario provided below. Write legibly and write your answer in your answer sheet. Given: A is the midpoint of segment MN. Prove: MA AN

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Related questions
Question
Statement
Reason
a and b are even numbers
Given
a = 2m and b 2n; where m and n are Definition of even numbers
%3D
any integers
3.
a + b is an odd number
Given
4 a+b 2k + 1; where k is any integer Definition of off numbers
Substitution (Statement 2 to Statement
4)
5 a+b 2m + 2n
6 a+b 2 (m + n); where m + n is any Factoring
integer
7 Therefore, the sum of two even Due to the contradiction between
statements 4 and 6, we can conclude
that the original statement is true.
numbers is also an even number
Statement 6 contradicts the definition of odd numbers expressed on statement 4; an
odd number is an integer in the form of 2k + 1, where k is any integer. Therefore, the
original statement is correct.
Activity 3: Can you prove it?
A. Directions: Use indirect proof to prove the scenario.
Given: A is not the midpoint of segment MN.
Prove: MA # AN
B. Directions: Using paragraph form, write the direct proof of the scenario provided
below. Write legibly and write your answer in your answer sheet.
Given: A is the midpoint of segment MN.
Prove: MA = AN
2.
1,
Transcribed Image Text:Statement Reason a and b are even numbers Given a = 2m and b 2n; where m and n are Definition of even numbers %3D any integers 3. a + b is an odd number Given 4 a+b 2k + 1; where k is any integer Definition of off numbers Substitution (Statement 2 to Statement 4) 5 a+b 2m + 2n 6 a+b 2 (m + n); where m + n is any Factoring integer 7 Therefore, the sum of two even Due to the contradiction between statements 4 and 6, we can conclude that the original statement is true. numbers is also an even number Statement 6 contradicts the definition of odd numbers expressed on statement 4; an odd number is an integer in the form of 2k + 1, where k is any integer. Therefore, the original statement is correct. Activity 3: Can you prove it? A. Directions: Use indirect proof to prove the scenario. Given: A is not the midpoint of segment MN. Prove: MA # AN B. Directions: Using paragraph form, write the direct proof of the scenario provided below. Write legibly and write your answer in your answer sheet. Given: A is the midpoint of segment MN. Prove: MA = AN 2. 1,
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