MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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According to the U.S. Census Bureau, the
English at home is 81%. The probability that a randomly selected household speaks only Spanish at
home is 12%.
a.) Find and interpret the probability that a randomly selected household speaks only English or
only Spanish at home.
b.) Find and interpret the probability that a randomly selected household speaks a language
other than only English or only Spanish at home.
c.) Can the probability that a randomly selected household speaks only Chinese at home is equal
to 8%? Why or why not?
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- Find the indicated complement. A certain group of women has a 0.33% rate of red/green color blindness. If a woman is randomly selected, what is the probability that she does not have red/green color blindness? .... What is the probability that the woman selected does not have red/green color blindness? (Type an integer or a decimal. Do not round )arrow_forwardAcross the United States, a staggering 72% of people are either overweight or obese. If 86 people are randomly selected, find the probability that ... (Round the answers to 4 decimal places.) a) ... exactly 58 are either overweight or obese: Incorrect0.0595 b) ... at most 63 of them are either overweight or obese: c) ... at least 66 of them are either overweight or obese:arrow_forwardThe table below shows the number of survey subjects who have received and not received a speeding ticket in the last year, and the color of their cars. Speeding Ticket No Speeding Ticket 102 188 112 178 214 366 Red Car Not Red Car Total Find the probability that a randomly chosen person: a) Has a red car. b) Has a speeding ticket. c) Has a speeding ticket given they have a red car. d) Has a red car given they have a speeding ticket. e) Has a red car and got a speeding ticket. f) Has a red car or got a speeding ticket. Total 290 290 580arrow_forward
- For a week, a clothing company tracks the amounts spent by its customers, with the results shown to the right. a) What is the probability that a randomly chosen customer spent $120 or more? b) What is the probability that a randomly chosen customer did not spend less than $80? c) What is the probability that a randomly chosen customer spent between $40 and $159.99? a) What formula should be used to find the probability that a randomly chosen customer spent $120 or more? O A. P($120 or more) = 1 - P($120 - $159.99) O B. P($120 or more) = P($120 - $159.99) O C. P($120 or more) = P($120 - $159.99) + P($160-$199.99) - P($200 or more) O D. P($120 or more) = P($120 - $159.99) + P($160 - $199.99) + P($200 or more) The probability that a randomly chosen customer spent $120 or more is (Simplify your answer.) b) What formula should be used to find the probability that a randomly chosen customer did not spend less than $80? O A. P(not less than $80)=P($80 - $119.99) O B. P(not less than $80) = 1…arrow_forwardThe table below shows the number of survey subjects who have received and not received a speeding ticket in the last year, and the color of their cars. Speeding Ticket No Speeding Ticket Total Red Car 199 162 361 Not Red Car 123 151 274 Total 322 313 635 Find the probability that a randomly chosen person:a) Has a red car. b) Has a speeding ticket. c) Has a speeding ticket given they have a red car. d) Has a red car given they have a speeding ticket. e) Has a red car and got a speeding ticket. f) Has a red car or got a speeding ticket.arrow_forwardThe table below shows the number of survey subjects who have received and not received a speeding ticket in the last year, and the color of their car. Find the probability that a randomly selected person: Speeding tcket No speeding Bcket Red car 15 135 Notred ca 45 470 fotal ts a) has a speeding ticket given they have a red car b) has a red car given they have a speeding ticket 8 88arrow_forward
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