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According to the ideal gas law, a 10.24 mol sample of xenon gas in a 0.8381 L container at 499.4 K should exert a pressure of 500.7 atm. What is the percent difference between the pressure calculated using the van der Waals' equation and the ideal pressure? For Xe gas, a 4.194 L²atm/mol² and b = 5.105×102 L/mol. = Percent difference | Pideal – Pvan der Waals | × 100 Pideal+Pvan der Waals % 2

According to the ideal gas law, a 10.24 mol sample of xenon gas in a 0.8381 L container at 499.4 K should exert a pressure of 500.7 atm. What is the percent difference between the pressure calculated using the van der Waals' equation and the ideal pressure? For Xe gas, a 4.194 L²atm/mol² and b = 5.105×102 L/mol. = Percent difference | Pideal – Pvan der Waals | × 100 Pideal+Pvan der Waals % 2

Chemistry & Chemical Reactivity
Chemistry & Chemical Reactivity
9th Edition
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter10: Gases And Their Properties
Section: Chapter Questions
Problem 53PS: In the text, it is stated that the pressure of 4.00 mol of Cl2 in a 4.00-L tank at 100.0 C should be...
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According to the ideal gas law, a 10.24 mol sample of xenon gas in a 0.8381 L container at 499.4 K should exert a pressure of 500.7 atm. What is the percent difference between the pressure calculated using the van der Waals' equation and the ideal pressure? For Xe gas, a 4.194 L²atm/mol² and b = 5.105×102 L/mol. = Percent difference | Pideal – Pvan der Waals | × 100 Pideal+Pvan der Waals % 2
Transcribed Image Text:According to the ideal gas law, a 10.24 mol sample of xenon gas in a 0.8381 L container at 499.4 K should exert a pressure of 500.7 atm. What is the percent difference between the pressure calculated using the van der Waals' equation and the ideal pressure? For Xe gas, a 4.194 L²atm/mol² and b = 5.105×102 L/mol. = Percent difference | Pideal – Pvan der Waals | × 100 Pideal+Pvan der Waals % 2
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