According to Newton's 1* Law, an object in motion will remain in motion. If an object is moving to the right at a constant velocity, what will applying a force in the following directions do to the object? a. An outside force acts on the object to the right. As a result, the object will O Remain moving at the same constant speed to the right O Speed up to the right O Slow down to the right

and How fast does the object end up moving at the end of the 2.22 s2.22 s? final speed of object:

A 30 kg cannonball is shot at a sailing ship. When it hits the wooden sides of the ship, it just barely punches through the wooden hull, applying a 200 000 N force to the ship the whole time it was stopping. → If the cannonball was originally travelling at 300m/s, how long would it take to completely stop in the hull of the ship assuming constant acceleration.

A.) An 85.0 kg subject is strapped into a 1950's rocket sled. Upon firing the rocket sled's acceleration is a constant 5.00 m/s2. Find the force the subject experiences during this acceleration B.) The rocket sled (from above) is braked to a complete stop from v = 5.0 m/s in 3.0 s. What is the force on the subject? Express this force in "g's"

X axis force (N) y axis acceleration (m/s^2) 10 6.0 20 12.5 30 19 a. Write an equation for the line B.What is the value of the force for an acceleration of 15 m/s^2 C. What is the acceleration when the force is 50.0N

A round with a mass of m=19.5g is fired out of a rifle that has a length L=1.18m. The round spends t=0.16s in the barrel.a. Calculate the magnitude of the round's accelration, in m/s2 as it travels thorugh the rilfe's barrel. You may assume that the acceleration is constant throughout the motion.b. What is the numerical value of the net force in newtons acting on the round?

A 60 kg person stands on a bathroom scale in an elevator. What does the scale read if the person is accelerating upward at 1.5 m/s²? +588 N O 678N 498 N ΟΟΝ

A car of mass 2,000 kg coasts down the highway with a constant velocity of v = 15.0 m/s. The car then goes over a hill 3.00 m vertically high. Which of these best describes the velocity of the car at the top of the hill?   a. it's 15.0 m/s   b. it's zero m/s   c. it's less than 15.0 m/s   d. it's greater than 15.0 m/s   e. none of these

Decont M ts. Using Newton's second law to calculate the acceleration of a key hanging in a car. You tape one end of a piece of string to the ceiling light of your car and hang a key with mass m on the other end of the string, A protractor taped to the light allows you to the angle the string makes with the vertical. Your friend drives the car while you make measurements. When the car has a constant acceleration with magnitude a toward the right, the string hangs at rest (relative to the car), making an angle ß with the vertical. (a) Derive an expression for the acceleration a in terms of the mass m and the measured angle B. (b) In particular, what is a when B = 45°? When B=0? Show your work that leads to your answer. Explain each step in your work to get the full credit. The equation with no ts. Calculate the magnitude and explanation will get your answer zero point. (c) bo direction of the total force acting on your body when the measured angle B is 45 degree or B = 45⁰. Assume the…

An object is moving forward with a constant velocity. Which statement about this object MUST be true? O The net force on the object is zero. O No forces are acting on the object. O The net force on the object is in the forward direction. The acceleration of the object is in the forward direction.