According to a study, the proportion of people who are satisfied with the way things are going in their lives is 0.88. Suppose that a random sample of 100 people is obtained. Complete parts (a) through (e) below. Click here to view the standard normal distribution table (page 1), Click here to view the standard normal distribution table (page 2). ... (a) Suppose the random sample of 100 people is asked, "Are you satisfied with the way things are going in your life?" Is the response to this question qualitative or quantitative? Explain. O A. The response is qualitative because the responses can be classified based on the characteristic of being satisfied or not. O B. The response is quantitative because the number of people satisfied can be counted. O C. The response is qualitative because the number of people satisfied can be counted. O D. The response is quantitative because the responses can be classified based on characteristic of being satisfied or not. (b) Explain why the sample proportion, p, is a random variable. What is the source of the variability? O A. The sample proportion p is a random variable because the value of p varies from sample to sample. The variability is due to the fact that people may not be responding to the question truthfully. O B. The sample proportion p is a random variable because the value of p represents a random person included in the sample. The variability is due to the fact that different people feel differently regarding their satisfaction. O C. The sample proportion p is a random variable because the value of p represents a random person included in the sample. The variability is due to the fact that people may not be responding to the question truthfully. O D. The sample proportion p is a random variable because the value of p varies from sample to sample. The variability is due to the fact that different people feel differently regarding their satisfaction. (c) Describe the sampling distribution of p, the proportion of people who are satisfied with the way things are going in their life. Be sure to verify the model requirements. V than 5% of the population size and np(1 - p) = 10, the distribution of p is V with =D and a, =0. Since the sample size is (Round to three decimal places as needed.) (d) In the sample obtained in part (a), what is the probability that the proportion who are satisfied with the way things are going in their life exceeds 0.91? The probability that proportion who are satisfied with the way things are going in their life exceeds 0.91 is. (Round to four decimal places as needed.) (e) Using the distribution from part (c), would it be unusual for a survey of 100 people to reveal that 80 or fewer people in the sample are satisfied with their lives? The probability that 80 or fewer people in the sample are satisfied is which unusual because this probability V less than (Round to four decimal places as needed.)

According to a survey in a country, 32% of adults do not own a credit card. Suppose a simple random sample of 600 adults is obtained. Complete parts (a) through (d) below. Click here to view the standard normal distribution table (page 1). Click here to view the standard normal distribution table (page 2). (a) Describe the sampling distribution of p, the sample proportion of adults who do not own a credit card. Choose the phrase that best describes the shape of the sampling distribution of p below. O A. Not normal because n <0.05N and np(1 – p)< 10 GB. Approximately normal because n<0.05N and np(1 - p) 2 10 CC. Not normal because ns0.05N and np(1 - p) 2 10 D. Approximately normal because n<0.05N and np(1 - p)< 10 Determine the mean of the sampling distribution of p. (Round to two decimal places as needed.) p Enter your answer in the answer box and then click Check Answer. ? 6. parts remaining Clear All Check Answer

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Listed below are systolic blood pressure measurements (mm Hg) taken from the right and left arms of the same woman. Assume that the paired sample data is a simple random sample and that the differences have a distribution that is approximately normal. Use a 0.05 significance level to test for a difference between the measurements from the two arms. What can be concluded? 143 140 141 136 133 Right arm Left arm 180 174 192 140 144 In this example, . is the mean value of the differences d for the population of all pairs of data, where each individual difference d is defined as the measurement from the right arm minus the measurement from the left arm. What are the null and alternative hypotheses for the hypothesis test? O A. Ho: Ha = 0 O B. Ho: Hd #0 0 = Prt :H O D. Ho: Hd =0 H O C. Ho: Ha 0 Identify the test statistic. t%3D (Round to two decimal places as needed.) Identify the P-value. P-value (Round to three decimal places as needed.) What is the conclusion based on the hypothesis test?…

In the US women between the ages of 18 to 50 have shoe sizes that approximately follow a normal distribution.  The approximate mean is shoe size 8.43 and the standard deviation is 1.35. Find the 90th percentile of this distribution, write the calculator function used to compute the result, and interpret it in a complete sentence.

1. Among American women aged 20 to 29 years, 10% are less than 60.8 inches tall, 80% are between 60.8 and 67.6 inches tall, and 10% are more than 67.6 inches tall. Assuming that the height distribution can adequately be approximated by a normal curve, find the mean and standard deviation of the distribution.

Is the difference between the mean annual salaries of statisticians in Region 1 and Region 2 more than $5000? To decide, you select a random sample of statisticians from each region. The results of each survey are shown to the right. At a = 0.10, what should you conclude? Region 1 X1 = $67,700 Region 2 X2 = $62,000 01 = $8825 02 = $9025 n1 = 48 n2 = 43 Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. ..... Choose the correct null and alternative hypotheses below. B. Ho: H1- H2 O C. Ho: H1 -H2 > 5000 Ha: H1 - H2 55000 O A. Ho: H1 - H2 > 5000 + 5000 Ha: H1 - H2 2 5000 Ha: H1 - H2 = 5000 O E. Ho: H1 - H2 2 5000 O D. Ho: H1 - H2 = 5000 Ha: H1 - H2 # 5000 F. Ho: µ1 - H2 5 5000 Ha: H1 - H2 > 5000 Ha: H1 - H2 В. Z

Is the difference between the mean annual salaries of statisticians in Region 1 and Region 2 more than $4000? To decide, you select a random sample of statisticians from each region. The results of each survey are shown to the right. At a = 0.10, what should you conclude? Region 1 X1 = $67,700 01 = $8875 Region 2 X2 = $61,000 02 = $9250 n1 = 48 n2 = 44 Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. Choose the correct answer below. O A. Reject Ho. At the 10% significance level, there is sufficient evidence to support the claim that the difference between the mean annual salaries is more than $4000. O B. Fail to reject Ho. At the 10% significance level, there is sufficient evidence to support the claim that the difference between the mean annual salaries is more than $4000. OC. Reject Ho. At the 10% significance level, there is insufficient evidence to support the claim that the difference between…

When you take samples of size n - 100 from a normally distributed population, what will likely be the shape of the distribution of sample means? Right Skewed Left Skewed Normal