According to a recent article about individuals who have credit cards, the mean number of cards per person with credit cards is 4.5. To test this result a random survey of 60 individuals who have credit cards was conducted. The survey only includes the number of credit cards per participant. The results of the survey are attached below. (a) What is the variable of interest in this study? Is it qualitative or quantitative? (b) Do the results of the survey imply that the mean number of cards per individual is less than 4.5? Use the a = 0.05 level of significance. E Click the icon to view the data from the survey. (a) What is the variable of interest in this study? Is it qualitative or quantitative? The variable of interest is number of credit cards.It is a quantitative variable. (b) Do the results of the survey imply that the mean number of cards per individual is less than 4.5? Use the a = 0.05 level of significance. State the null and alternative hypotheses. Họ: H 4.5 H;: < 4.5 (Type integers or decimals.) Determine the t-statistic. to = - 1.48 (Round to two decimal places as needed.) Determine the P-value. P-value = 0.072 (Round to three decimal places as needed.) Make a conclusion regarding the hypothesis. The P-value is V than the level of significance. V the null hypothesis. There sufficient evidence to claim that the mean number of credit cards is 4.5.
According to a recent article about individuals who have credit cards, the mean number of cards per person with credit cards is 4.5. To test this result a random survey of 60 individuals who have credit cards was conducted. The survey only includes the number of credit cards per participant. The results of the survey are attached below. (a) What is the variable of interest in this study? Is it qualitative or quantitative? (b) Do the results of the survey imply that the mean number of cards per individual is less than 4.5? Use the a = 0.05 level of significance. E Click the icon to view the data from the survey. (a) What is the variable of interest in this study? Is it qualitative or quantitative? The variable of interest is number of credit cards.It is a quantitative variable. (b) Do the results of the survey imply that the mean number of cards per individual is less than 4.5? Use the a = 0.05 level of significance. State the null and alternative hypotheses. Họ: H 4.5 H;: < 4.5 (Type integers or decimals.) Determine the t-statistic. to = - 1.48 (Round to two decimal places as needed.) Determine the P-value. P-value = 0.072 (Round to three decimal places as needed.) Make a conclusion regarding the hypothesis. The P-value is V than the level of significance. V the null hypothesis. There sufficient evidence to claim that the mean number of credit cards is 4.5.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:According to a recent article about individuals who have credit cards, the mean number of cards per person with credit cards is 4.5. To test this result a random survey of 60 individuals
who have credit cards was conducted. The survey only includes the number of credit cards per participant. The results of the survey are attached below.
(a) What is the variable of interest in this study? Is it qualitative or quantitative?
(b) Do the results of the survey imply that the mean number of cards per individual is less than 4.5? Use the a = 0.05 level of significance.
Click the icon to view the data from the survey.
.....
(a) What is the variable of interest in this study? Is it qualitative or quantitative?
The variable of interest is number of credit cards.It is a quantitative variable.
(b) Do the results of the survey imply that the mean number of cards per individual is less than 4.5? Use the a = 0.05 level of significance. State the null and alternative hypotheses.
1 :0H
H1: H
4.5
く
4.5
(Type integers or decimals.)
Determine the t-statistic.
to =
- 1.48 (Round to two decimal places as needed.)
Determine the P-value.
P-value = 0.072 (Round to three decimal places as needed.)
Make a conclusion regarding the hypothesis.
The P-value is
than the level of significance.
the null hypothesis. There
sufficient evidence to claim that the mean number of credit cards is
4.5.
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