Acceleration of a Car The distance s (in feet) covered by a car t seconds after starting is given by the following function -t³ + 14t² + 18t (0 ≤ t ≤ 6) Find a general expression for the car's acceleration (in ft/sec³) at any time t (0 ≤ t ≤ 6). s"(t) = -31²+28t+18 S = -t X At what time t (in sec) does the car begin to decelerate? (Round your answer to one decimal place.) t = 18 X sec
Acceleration of a Car The distance s (in feet) covered by a car t seconds after starting is given by the following function -t³ + 14t² + 18t (0 ≤ t ≤ 6) Find a general expression for the car's acceleration (in ft/sec³) at any time t (0 ≤ t ≤ 6). s"(t) = -31²+28t+18 S = -t X At what time t (in sec) does the car begin to decelerate? (Round your answer to one decimal place.) t = 18 X sec
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section4.6: Variation
Problem 2E
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hello, Just need help with understanding what im not doing correctly as in the screenshot they are wrong
![Acceleration of a Car The distance s (in feet) covered by a car t seconds after starting is given by the following function.
−t³ + 14t² + 18t
(0 ≤ t ≤ 6)
Find a general expression for the car's acceleration (in ft/sec³) at any time t (0 ≤ t ≤ 6).
−3+²+28t+18
s"(t):
=
S =
At what time t (in sec) does the car begin to decelerate? (Round your answer to one decimal place.)
t = 18
X sec](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F67fbd5d8-0948-4b18-8071-fc784645c75f%2Fdbc0cf19-8860-4bfe-aab4-91c0e9f2930e%2F5pqvdc_processed.png&w=3840&q=75)
Transcribed Image Text:Acceleration of a Car The distance s (in feet) covered by a car t seconds after starting is given by the following function.
−t³ + 14t² + 18t
(0 ≤ t ≤ 6)
Find a general expression for the car's acceleration (in ft/sec³) at any time t (0 ≤ t ≤ 6).
−3+²+28t+18
s"(t):
=
S =
At what time t (in sec) does the car begin to decelerate? (Round your answer to one decimal place.)
t = 18
X sec
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