A 8.00-kg object undergoes an acceleration given by = (4.00 î + 9.00 ĵ) m/s2. Find the resultant force acting on the object. Find the magnitude of the resultant force.
A 8.00-kg object undergoes an acceleration given by = (4.00 î + 9.00 ĵ) m/s2. Find the resultant force acting on the object. Find the magnitude of the resultant force.
Physics for Scientists and Engineers with Modern Physics
10th Edition
ISBN:9781337553292
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter3: Vectors
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Hi, I have this question answered with the following data:
Question: A 8.00-kg object undergoes an acceleration given by = (4.00 î + 9.00 ĵ) m/s2.
- Find the resultant force acting on the object.
- Find the magnitude of the resultant force.
Given data:
Given data: mass (m) = 8.00 kg, acceleration a = (4.00 î + 9.00 ĵ) m/s2
Required: The resultant force and magnitude of the resultant force
According to newton's second law of motion
F = ma= 8.00 kg(4.00 î + 9.00 ĵ) m/s2= (32.0 î + 72.0 ĵ) N
The resultant force acting on the object is (32.0 î + 72.0 ĵ) N
[can you please explain to me how do you arrived to the 78.8N] - I don't get it! Thanks
The magnitude of the resultant force
F = Fx2 + Fy2= 32.0 N2+72.0 N2= 78.79 N≈ 78.8 N
The magnitude of the resultant force is equals to 78.8 N
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