A 44.0-cm diameter disk rotates with a constant angular acceleration of 2.60 rad/s2. It starts from rest at t = 0, and a line drawn from the center of the disk to a point P on the rim of the disk makes an angle of 57.3° with the positive x-axis at this time. (a) At t = 2.38 s, find the angular speed of the wheel. rad/s (b) At t = 2.38 s, find the magnitude of the linear velocity and tangential acceleration of P. linear velocity m/s tangential acceleration m/s2 (c) At t = 2.38 s, find the position of P (in degrees, with respect to the positive x-axis).
Angular speed, acceleration and displacement
Angular acceleration is defined as the rate of change in angular velocity with respect to time. It has both magnitude and direction. So, it is a vector quantity.
Angular Position
Before diving into angular position, one should understand the basics of position and its importance along with usage in day-to-day life. When one talks of position, it’s always relative with respect to some other object. For example, position of earth with respect to sun, position of school with respect to house, etc. Angular position is the rotational analogue of linear position.
A 44.0-cm diameter disk rotates with a constant
rad/s
(b) At t = 2.38 s, find the magnitude of the linear velocity and tangential acceleration of P.
| linear velocity | m/s |
| tangential acceleration | m/s2 |
(c) At t = 2.38 s, find the position of P (in degrees, with respect to the positive x-axis).
Your response differs from the correct answer by more than 10%. Double check your calculations.° counterclockwise from the +x-axis
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