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hello, I have attached a question with the answers. I don't need the answer, I need to know why the lecturer did each step and what process I should use to answer similar questions.
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Transcribed Image Text:A4) The point O is 8 m above a horizontal plane. A particle P is projected from 0. After projection, the
horizontal and vertically upwards displacements of P from O are x m and y m, respectively. The equation
of the trajectory of P is
y = 2x – x? ----(1).
(i)
Find the value of x for the point where P strikes the plane.
Find the angle and speed of projection of P.
(ii)
Calculate the speed of P immediately before it strikes the plane.
(ii)
(i)
y = 2x – x?
: -8 = 2x – x²
= x = 4 m
(ii)
Equation for trajectory: y = tan e x –:
-- (2)
2v, cos? e
= 0 = tan-(2) = 63.4°
Comparing to (2) to (1): tan e = 2
and
2v cos? e
= vo = 4.95 m/s
= 1
(iii)
v² = v3 – 2gy = 4.952 – 2(9.81)(-8)
= v = 13.5 m/s
= 181.485
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