A 0.269-kg volleyball approaches a player horizontally with a speed of 12.0 m/s. The player strikes the ball with her fist and causes the ball to move in the opposite direction with a speed of 23.0 m/s. (a) What impulse is delivered to the ball by the player? (Take the direction of final velocity to be the positive direction. Indicate the direction with the sign of your answer.) (b) If the player's fist is in contact with the ball for 0.0600 s, find the magnitude of the average force exerted on the player's fist.

When spiking a volleyball, a player changes the velocity of the ball from 4.2 m/s to -24 m/s; along a certain direction. If the impulse delivered to the ball by the player is -9.3 kg.m/s, what is the mass of the volleyball?

A ball falls from height of 20.0 m, hits the floor, and rebounds vertically upward to height of 15.0 m. Assume that m ball = 0.385 kg. (a) What is the impulse (in kg. m/s) delivered to the ball by the floor? magnitude x direction 979.1 Assume the only impulse delivered to the ball is from the floor, which equals the change in momentum of the ball. Find the initial and final speeds of the ball using conservation of mechanical energy, and calculate Ap noting that all the motion is in the y-direction. kg. m/s up ✓✓ (b) If the ball is in contact with the floor for 0.0300 seconds, what is the average force (in N) the floor exerts on the ball? magnitude 19.223 x Use the impulse-momentum theorem and the result from part (a) to find the force, given that the contact time interval is 0.0300 s. N up direction ✓✓

A 0.280 kg volleyball approaches a player horizontally with a speed of 15.0 m/s. The player strikes the ball with her fist and causes the ball to move in the opposite direction with a speed of 22.0 m/s. a) what impulse is delivered to the ball by the player? b) if the players fist is in contact with the ball for 0.600s, find the magnitude of the average force exerted on the players' fist.