A.3.3 Given the function governing the motion of a simple pendulum with mass 0.5 kg is 0 = 0.5 cos(0.5t+T/2) (in rad), determine: a. the period of oscillation; d. the position and linear velocity of the bob at t = 0; Answer: 4s. Answer: Oi rad and -3.12 m/s. b. the length of the pendulum; e. the kinetic energy when the angle is 0 = 0.2 rad Answer: 3.98 m. Answer: 2.045 J. c. the maximum angle reached; f. the total mechanical energy of the pendulum. Answer: 0.5 rad or 28.66°. Answer: 2.4 J.

College Physics
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Chapter13: Vibrations And Waves
Section: Chapter Questions
Problem 65AP: A simple pendulum has mass 1.20 kg and length 0.700 m. (a) What is the period of the pendulum near...
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А.3.3
Given the function governing the motion of a simple pendulum with mass 0.5 kg is 0 =
0.5 cos(0.5Tt+T /2)
(in rad), determine:
a. the period of oscillation;
d. the position and linear velocity of the bob at t = 0;
Answer: 4 s.
Answer: Oi rad and -3.12 m/s.
b. the length of the pendulum;
e. the kinetic energy when the angle is 0 = 0.2 rad
Answer: 3.98 m.
Answer: 2.045 J.
c. the maximum angle reached;
f. the total mechanical energy of the pendulum.
Answer: 0.5 rad or 28.66°.
Answer: 2.4 J.
Transcribed Image Text:А.3.3 Given the function governing the motion of a simple pendulum with mass 0.5 kg is 0 = 0.5 cos(0.5Tt+T /2) (in rad), determine: a. the period of oscillation; d. the position and linear velocity of the bob at t = 0; Answer: 4 s. Answer: Oi rad and -3.12 m/s. b. the length of the pendulum; e. the kinetic energy when the angle is 0 = 0.2 rad Answer: 3.98 m. Answer: 2.045 J. c. the maximum angle reached; f. the total mechanical energy of the pendulum. Answer: 0.5 rad or 28.66°. Answer: 2.4 J.
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