a. Write the solution set to the following equation in parametric vector form (consider ₁ to be the basic variable). x₁9x2-3x3 = 0 x = 1x5 b. Write the solution set to the following equation in parametric vector form (consider ₁ to be the basic variable). = x2 x1 - 9x2-3x3 +xs == 1 x +x₂ c. How do the graphs of the solutions sets to the equations in parts a and b differ?

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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a. Write the solution set to the following equation in parametric vector form (consider ₁ to be
the basic variable).
x19x2
3x3 = 0
x 5
x = x₂
b. Write the solution set to the following equation in parametric vector form (consider ₁ to be
the basic variable).
x1 - 9x2 - 3x3
+xs
= -1
x
+x₂
c. How do the graphs of the solutions sets to the equations in parts a and b differ?
Transcribed Image Text:a. Write the solution set to the following equation in parametric vector form (consider ₁ to be the basic variable). x19x2 3x3 = 0 x 5 x = x₂ b. Write the solution set to the following equation in parametric vector form (consider ₁ to be the basic variable). x1 - 9x2 - 3x3 +xs = -1 x +x₂ c. How do the graphs of the solutions sets to the equations in parts a and b differ?
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