a. Write the solution set to the following equation in parametric vector form (consider ₁ to be the basic variable). x₁9x2-3x3 = 0 x = 1x5 b. Write the solution set to the following equation in parametric vector form (consider ₁ to be the basic variable). = x2 x1 - 9x2-3x3 +xs == 1 x +x₂ c. How do the graphs of the solutions sets to the equations in parts a and b differ?
a. Write the solution set to the following equation in parametric vector form (consider ₁ to be the basic variable). x₁9x2-3x3 = 0 x = 1x5 b. Write the solution set to the following equation in parametric vector form (consider ₁ to be the basic variable). = x2 x1 - 9x2-3x3 +xs == 1 x +x₂ c. How do the graphs of the solutions sets to the equations in parts a and b differ?
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter9: Quadratic Functions And Equations
Section9.7: Solving Systems Of Linear And Quadratic Equations
Problem 21PPS
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please answer
![a. Write the solution set to the following equation in parametric vector form (consider ₁ to be
the basic variable).
x19x2
3x3 = 0
x 5
x = x₂
b. Write the solution set to the following equation in parametric vector form (consider ₁ to be
the basic variable).
x1 - 9x2 - 3x3
+xs
= -1
x
+x₂
c. How do the graphs of the solutions sets to the equations in parts a and b differ?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc2e97f32-5988-4deb-9547-eb6ce37eb1f3%2F161c7e20-1646-4ee0-8e3b-78a496d2c693%2F5qcl6z_processed.png&w=3840&q=75)
Transcribed Image Text:a. Write the solution set to the following equation in parametric vector form (consider ₁ to be
the basic variable).
x19x2
3x3 = 0
x 5
x = x₂
b. Write the solution set to the following equation in parametric vector form (consider ₁ to be
the basic variable).
x1 - 9x2 - 3x3
+xs
= -1
x
+x₂
c. How do the graphs of the solutions sets to the equations in parts a and b differ?
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