а. Where is the electric field stronger, point A or point B? Explain using physical reasoning. b. If a proton is fired from point B toward point C, will its speed at C be greater than, less than, or the same as B? Explain using physical reasoning.

а. Where is the electric field stronger, point A or point B? Explain using physical reasoning. b. If a proton is fired from point B toward point C, will its speed at C be greater than, less than, or the same as B? Explain using physical reasoning.

Related questions

Q: Consider a positive charge Q₁ of magnitude 7.5 µC fixed at the origin with another positive charge…

Q: Consider a positive charge Q₁ of magnitude 1 µC fixed at the origin with another positive charge Q2…

Q: Which of the following concepts support the fact that the electric field is the negative gradient of…

A: In electrostatics, the electric field is indeed the negative gradient of the electric potential…

Q: he Earth is a charged sphere. Near the surface of the Earth, the electric field has a constant value…

A: Given Electric field is E= 150 N/C Charge is q= 2 µC=2x10-6 C Distance is d= 5 m

Q: EXERCISE A constant electric field with magnitude 1.50 x 10³ N/C is pointing in the positive…

A: Concept: The magnitude of a constant electric field is given to be 1.50×103 N/C in the positive…

Q: A positively charged particle is in the center of a parallel-plate capacitor that has charge ±Q on…

A: Concept: A push or pull upon an object resulting from the objects interaction with another object is…

Q: A proton and an electron are separately placed in a uniform electric field created inside a pair of…

A: The correct choice is option (2).

Q: a. Calculate the maximum torque experienced by this electric pole! b. If the direction of the dipole…

Q: 11. Two electrons are pushed together until they are 0.02 m apart. a. What is the Electric Force…

A: Given :- q1 = q2 = charge of electron = -1.60217662 × 10-19 coulombs r = 0.02 m K =8.988×109…

Q: A point charge q1 = +2.2μC is stationary at the origin. A second point charge q2 = −3.4μC moves from…

Q: 1. Small charges q1 = + 7.5µC and q2 = - 2.5µC are brought in from infinity and fixed on the x axis…

Q: Three identical point charges (+34 µC) are placed at the corners of an equilateral triangle that has…

A: Given: charges q1=q2=q3=34μC=34*10-6C side of equilateral triangle = distance between charges r = 20…

Q: 4. A particle with a charge of +4.20 nC is in a uniform electric field E directed to the left. It is…

Q: 1. A point charge q1 = +5.60 µC is at origin. How far should the second point charge of +8.10 µC be…

Q: x=+2L x=0 x=+L P A non-conducting rod is along the x-axis between x=0 and x=+L. The linear charge…

A: Dear student The potential due to a charge q at a distance r is given by : V = Kq/r For a…

Q: In the figure an electric dipole swings from an initial orientation i (8₁ = 19.0°) to a final…

Q: Learning Task 3 Solve the following problems. Show your solution. 1. Two-point charges Qi = 4.5 µC…

Q: State and prove Gauss Theorem. Two-point charges q1 & q2 are 5m apart and their combined char,…

A: You ask me to to do a question b) So we can solve the question no b) only. We know that the formula…

Q: n electron is fired in the positive y-direction from x= -3.00 cm in a constant electric field with…

A: Given: X=-3 cm E=1.88×103 N/C X=2 cm

Q: The diagram beside shows point P in the presence of two charges of +Q. What is the direction of the…

Q: A point charge, q = -8.0 µC, moves for a distance of 80 cm at an angle of 900 relative to the…

A: The direction 90° to the uniform electric field forms a equi potential surface. The potential on all…

Q: Use the worked example above to help you solve this problem. A proton is released from rest at x=…

A: Initially, a proton is released from rest, at x=-2 cm or -0.02 m, under the influence of an external…

Q: 1. Consider that the earth and the atmosphere form a parallel plate of charges. Where the electric…

A: As it is a multiple question. I answer the first question. Please resubmit the second question…

Q: 7. A proton is released from rest at point A in a uniform electric field that has a magnitude of…

A: electric field = E = 5 X 104 V/mdisplacement = d = 0.5 mcharge of proton = q = 1.6 x 10-19 Cmass of…

Q: Starting from rest, a proton was accelerated by an electric field. After a distance of 1.35 m the…

A: Given Data Distance covered by the proton is d=1.35 m Final speed of the proton is vf=1.97×105 m/s…

Q: A proton has an initial speed of 5.0×105 m/s. Please give a correct/clear explanation of all…

Q: What is the magnitude of the electric field (assumed to be uniform) in the region between the…

A: Given: The separation between capacitor plates is d=45 mm Potential difference between capacitor…

Q: 1. Small charges q1 = + 7.5µC and q 2 = - 2.5µC are brought in from infinity and fixed on the x axis…

Q: 3. Consider the electric field between two parallel plates to be uniform, i.e., same magnitude and…

Q: Calculate the speed of a proton that is accelerated from rest through an electric potential…

A: Given data: The charge on electron and proton is: q = 1.6×10-19 C The mass of an electron is: me =…

Q: You place a particle of charge q at the origin and another of -2q at x = -d m. a. Write an…

Question

3. A set of equipotential lines is shown below.
а.
Where is the electric field stronger, point A or point B? Explain using physical
reasoning.
b.
If a proton is fired from point B toward point C, will its speed at C be greater
than, less than, or the same as B? Explain using physical reasoning.
A.
50И
40V
30V
20V
10V
•B

Expert Solution

Step 1

Electric Field

The electric field is a region in space around a charge or a system of charges such that if a test charge is brought into the region, it will experience a force due to the source charges.

The magnitude of the electric field strength due to a point charge $q$ at a distance $r$ from it is

$E = \frac{1}{4 π ε_{o}} \frac{q}{r^{2}}$

Electric Potential

The electric potential at a point is the amount of work done by an external agency in bringing a unit positive charge from infinity to that point under the influence of the electric field produced by other charges.

The electric potential due to a point charge $q$ at a distance $r$ from it is

$V = \frac{1}{4 π ε_{o}} \frac{q}{r}$

If we have two equipotential surfaces such that the potential difference between the equipotential surfaces is $d V$ and the distance between them is $d r$ , the electric field between the two surfaces is

$E = - \frac{d V}{d r}$

Here $\frac{d V}{d r}$ is known as the potential gradient.