a. Two brass rods used as compression members, each of 3-m effective length with pin end, have the cross sections shown in Figure Q5a. Determine the wall thickness of the hollow square rod for which the rods have the same critical buckling load. P O 40 mm 60 mm

Problem 2 Assume that Member AB may be considered as long and slender and consider only Euler buckling. What is the critical Euler buckling load and will Member AB buckle? What is the factor of safety of the compressive load with respect to the critical buckling load? Assume buckling only occurs in the plane of the paper. Note: E-30e6psi, I-6.36e-3 in', A-2.83 in², LAB-41.6 in, FAB-540 lb (compression). Also Member OB is 36 inches (3 ft) long. F=270 lbf 3 ft 3 60 A = 45270 LB, n = 83.8, buckles 48400 LB, n = A. Per B. Per C. Per = 1088 LB, n 897, does not buckle 2.02, does not buckle D. Per = 544 LB, n = 0.993, buckles E. None of These

Consider the steel truss and member cross-section presented in figures below. All the members of the truss have the same cross-section as shown in the figure to the right. They all also have a Young's Modulus of 210 GPa. What can the highest value of force F be before member AC fails by buckling? Force 1AN - 300 mm 40° 4 m $35 mm 7m 300 mm 8 m 35 mm 35 mm 35 mm Please provide your answer in kN.

Consider two types of a column cross-section: a hollow square and a hollow circular section. In both cases the wall thickness is 6 mm and the area occupied by the load-bearing material is 965 mm². Find which of these two column types produces a better buckling performance with relevant calculations supporting your answer. Answer The outer size of the hollow square section can be calculated as mm • The outer diameter of the hollow circular section can be calcualted as . mm The second moment of area for the hollow square section can be calculated as mm The second moment of area for the hollow circle section can be calculated as mm Find which of these two column types produces a better buckling performance. O Hollow Circular Section O Hollow Square Section

2" Problem 5: For the component shown in the figure. Where is the critical location? What steel do you recommend based on yielding and factor of safety n=3. (F=1000 lb) == 24243,936N Paper Buckling => (5,00016) (1125/2) J 1/64 (1125/9 = 26075,95 1.25" r = 0.06" F 51 Per = ('T ES 02 2F T = 5F lb - in 3350 72518.87 86000 = 98.99) ² 2n, 3