A. The text shows that: ∂U/∂T)V = ∂U/∂V)P. Can you show that: ∂H/∂T)V = ∂H/∂T)P ? Hint: start with: ∂H = ∂H/∂T)P ∂T +... B. Starting with: ∂H/∂P)T = ∂(U+PV)/ ∂P)T , can you show that ∂U/∂P)T = ∂H/∂P)T ? Hint: you will need to use the perfect gas law.

Please answer the following question. If graph needed please include it as well.

Two nitro (NO₂) groups are chemically bonded to a patch of surface. They can't move to another location on the surface, but they can rotate (see sketch at right). It turns out that the amount of rotational kinetic energy each NO₂ group can have is required to be a multiple of a, where * = 1.0 × 10-24 J. In other words, each NO₂ group could have & of rotational kinetic energy, or 2, or 3, and so forth - but it cannot have just any old amount of rotational kinetic energy. Suppose the total rotational kinetic energy in this system is initially known to be 68. Then, some heat is removed from the system, and the total rotational kinetic energy falls to 64€. Calculate the change in entropy. Round your answer to 3 significant digits, and be sure it has the correct unit symbol. 0 0.0 X H olo G की Two rotating NO, groups bonded to a surface.