a. The base of the cone should be a circle. Explain why the circumference of the base is 57. b. Find the radius of the base. c. What is the area of the original circle?

Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter7: Applying Fractions
Section7.1: Ratios
Problem 28WE
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a. The base of the cone should be a circle. Explain why the
circumference of the base is 5T.
b. Find the radius of the base.
c. What is the area of the original circle?
d. What is the area of the circle with one part missing?
e. Describe the surface area of the cone. Use your description t
find the surface area, including the base.
Scre
Screens
Show in
Transcribed Image Text:a. The base of the cone should be a circle. Explain why the circumference of the base is 5T. b. Find the radius of the base. c. What is the area of the original circle? d. What is the area of the circle with one part missing? e. Describe the surface area of the cone. Use your description t find the surface area, including the base. Scre Screens Show in
• Draw a circle with a radius of 3 inches.
• Mark the circumference of the circle into
six equal parts.
TT
• The circumference of the circle is
2(T) (3) = 67. So each of the six parts
on the circle has a length of 7. Label
each part.
• Cut out one part as shown. Then, make a cone.
ㅠ
πT
TT
TT
k
π
3 in.
E
#
+
k
Transcribed Image Text:• Draw a circle with a radius of 3 inches. • Mark the circumference of the circle into six equal parts. TT • The circumference of the circle is 2(T) (3) = 67. So each of the six parts on the circle has a length of 7. Label each part. • Cut out one part as shown. Then, make a cone. ㅠ πT TT TT k π 3 in. E # + k
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