a. Solve by back-substitution: 3x1 + 3x2 + X3 = 12, -4x₂-3x3 = -10, 4. 2x3 = = b. Solve by forward-substitution: = 3x₁ 15, 2x₁ - x₂ = 10, 5x₁ + x₂ - 2x3 = 5.

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