a. In an animal shelter, 100 cats and 50 dogs are being accommodated. Table below shows age group of thecats and dogs.DogsCatsTotalOld4070110Young103040Total50100150Test-statisticsZ=-p)0.8-0.7/0.7333>|-0,=1. 3055P-ValueP – Value = 2 x P (Z > 1.3055)=2 x 0.0959=0. 1918ConclusionP-value 0.1918 is greater than the level of significance 0.05, therefore do not reject the nullhypotheses. null hypotheses is accepted. Therefore the probability of being old in dogs andcats is equal.What is the power of the test in part a?

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Answered: a. In an animal shelter, 100 cats and…

a. In an animal shelter, 100 cats and 50 dogs are being accommodated. Table below shows age gro cats and dogs. Dogs Cats Total Old 40 70 110 Young 10 30 40 Total 50 100 150 Test-statistics

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Concept explainers

Counting Principles

In statistics, the counting principle can be said to be the concept in which the quantity of an item is determined. There can be a single item, or a group of items, or items that are related to each other. In every possible set of items, the quantity of the possible item groups or their sorting measures can be determined with counting principles.

Question

a. In an animal shelter, 100 cats and 50 dogs are being accommodated. Table below shows age group of the
cats and dogs.
Dogs
Cats
Total
Old
40
70
110
Young
10
30
40
Total
50
100
150
Test-statistics
Z=
-p)
0.8-0.7
/0.7333>
|-0,
=1. 3055
P-Value
P – Value = 2 x P (Z > 1.3055)
=2 x 0.0959
=0. 1918
Conclusion
P-value 0.1918 is greater than the level of significance 0.05, therefore do not reject the null
hypotheses. null hypotheses is accepted. Therefore the probability of being old in dogs and
cats is equal.
What is the power of the test in part a?

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