MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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- Test the claim that the proportion of men who own cats is larger than 20% at the .01 significance level. The null and alternative hypothesis would be: Ho: P 0.2 Hop 0.2 Hoμ = 0.2 H₁: p0.2 H₁ : μ 0.2 (to 2 decimals) (to 2 decimals) Ho: p = 0.2 0 H₁: p < 0.2arrow_forwardUse the given information to find the P-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis). The test statistic in a two-tailed test is z=1.95. A. 0.9744; fail to reject the null hypothesis B. 0.0512; fail to reject the null hypothesis C. 0.0512; reject the null hypothesis D. 0.0256; reject the null hypothesisarrow_forwardB. Identify the test statistic. ______ C. Identify the P-value. ____ D. What is the conclusion for this test? The P-value is (greater than/less than) the significance level α, so (reject/ fail to reject) the null hypothesis. There is (sufficient/ insufficient) evidence to support the claim that vinyl gloves have a greater virus leak rate than latex gloves.arrow_forward
- Test the claim that the mean GPA of night students is significantly different than 2.3 at the 0.05 significance level.The null and alternative hypothesis would be: H0:μ=2.3H0:μ=2.3H1:μ>2.3H1:μ>2.3 H0:p=0.575H0:p=0.575H1:p>0.575H1:p>0.575 H0:μ=2.3H0:μ=2.3H1:μ<2.3H1:μ<2.3 H0:p=0.575H0:p=0.575H1:p≠0.575H1:p≠0.575 H0:μ=2.3H0:μ=2.3H1:μ≠2.3H1:μ≠2.3 H0:p=0.575H0:p=0.575H1:p<0.575H1:p<0.575 The test is: two-tailed left-tailed right-tailed Based on a sample of 80 people, the sample mean GPA was 2.27 with a standard deviation of 0.02The test statistic is: (to 2 decimals)The positive critical value is: (to 2 decimals)Based on this we: Fail to reject the null hypothesis Reject the null hypothesisarrow_forwardIarrow_forwardProf. Johnson conducts a hypothesis test on whether the proportion of all UBC students who bike to school (denoted as p) equals 30%. Specifically, Prof.Johnson has H0:p=0.3 versus HA:p≠0.3. He obtains a P-value of 0.01. On the other hand, Prof. Smith would like to test if there is sufficient evidence to support that p is greater than 0.3 at the 10% significance level. Based on Prof. Johnson's result, will the null hypothesis of Prof. Smith's test be rejected? A. There is insufficient information to tell.B. Yes.C. No.arrow_forward
- The test statistic of z=1.54 is obtained when testing the claim that p=0.723. a. Identify the hypothesis test as being two-tailed, left-tailed, or right-tailed. b. Find the P-value. c. Using a significance level of a=0.10, should we reject H0 or should we fail to reject H0?arrow_forwardTest the claim that the mean GPA of night students is significantly different than 2 at the 0.01 significance level. The null and alternative hypothesis would be: Но: р > 0.5 Нo: 2 H1:p > 0.5 H1:µ # 2 H1:p+ 0.5 H1:µ 2 The test is: right-tailed left-tailed two-tailed Based on a sample of 55 people, the sample mean GPA was 2.05 with a standard deviation of 0.03 The p-value is: (to 2 decimals)arrow_forwardThe value obtained for the test statistic, z, in a one-mean z-test is given. Whether the test is two tailed, left tailed, or right tailed is also specified. For parts (a) and (b), determine the P-value and decide whether, at the 1% significance level, the data provide sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis. a. The test statistic in a two-tailed test is z = -0.93. The P-value is (Round to three decimal places as needed.) ... sufficient evidence to reject the null hypothesis in favor of the significance level. At the 1% significance level, the data the alternative hypothesis because the obtained P-value is b. The test statistic in a two-tailed test is z = 0.61. The P-value is (Round to three decimal places as needed.) sufficient evidence to reject the null hypothesis in favor of the significance level. At the 1% significance level, the data the alternative hypothesis because the obtained P-value is Time Remaining: 01:57:58 Mandarrow_forward
- Assume a significance level of a = 0.05 and use the given information to complete parts (a) and (b) below. Original claim: More than 58% of adults would erase all of their personal information online if they could. The hypothesis test results in a P-value of 0.1921. a. State a conclusion about the null hypothesis. (Reject Ho or fail to reject Ho.) Choose the correct answer below. O A. Reject Ho because the P-value is greater than a. O B. Reject Ho because the P-value is less than or equal to a. O C. Fail to reject Ho because the P-value is less than or equal to a. O D. Fail to reject Ho because the P-value is greater than a. b. Without using technical terms, state a final conclusion that addresses the original claim. Which of the following is the correct conclusion? O A. There is sufficient evidence to support the claim that the percentage of adults that would erase all of their personal information online if they could is more than 58%. O B. There is not sufficient evidence to support…arrow_forwardTest the claim that the mean GPA of night students is smaller than 2.5 at the 0.01 significance level.The null and alternative hypothesis would be: H0:p=0.625H0:p=0.625H1:p≠0.625H1:p≠0.625 H0:p≥0.625H0:p≥0.625H1:p<0.625H1:p<0.625 H0:μ≤2.5H0:μ≤2.5H1:μ>2.5H1:μ>2.5 H0:μ≥2.5H0:μ≥2.5H1:μ<2.5H1:μ<2.5 H0:p≤0.625H0:p≤0.625H1:p>0.625H1:p>0.625 H0:μ=2.5H0:μ=2.5H1:μ≠2.5H1:μ≠2.5 The test is: right-tailed two-tailed left-tailed Based on a sample of 35 people, the sample mean GPA was 2.48 with a standard deviation of 0.03The test statistic is: (to 2 decimals)The p-value is: (to 2 decimals)Based on this we: Reject the null hypothesis Fail to reject the null hypothesisarrow_forward
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