a. Find the particular solution with initial condition Z(0) = 0. T dT T == dx pg b. Use T(x) to determine the thickness of the glacier at 1 km. Then graph the function T Desmos and the solution point. Make sure to scale the graph so I can see it well.

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**Understanding Glacier Thickness through Differential Equations**

In this lesson, we will explore how to determine the thickness of a glacier using differential equations. The glacier thickness is represented by the function \( T(x) \), and is influenced by the variable \( \tau(x) \).

### Problem Statement

We are given the glacier thickness differential equation with:
\[ \tau(x) = 0.3x(1000 - x) \, \text{N/m} \]

With parameters:
- \( \rho = 917 \, \text{kg/m}^3 \)
- \( g = 9.8 \, \text{m/s}^2 \)

**Tasks:**

1. **Finding the Particular Solution:**
   - **Initial Condition:** \( T(0) = 0 \).
   - **Differential Equation:**
     \[
     \frac{dT}{dx} = \frac{\tau}{\rho g}
     \]

2. **Analyzing Glacier Thickness:**
   - Calculate the glacier's thickness at 1 km.
   - Graph the function \( T(x) \) using Desmos, highlighting the solution point, and ensure the graph is appropriately scaled for clarity.

### Visual Explanation

The equation indicates that the rate of change in glacier thickness, \( \frac{dT}{dx} \), is equal to the stress \( \tau \) divided by the product of density \( \rho \) and gravitational acceleration \( g \).

#### Guidance for Graphing:
- Use appropriate scaling in Desmos to visualize changes in \( T(x) \).
- Highlight the point where \( x = 1 \) km to examine the glacier thickness at this position.

By following these steps, students will gain a better understanding of how mathematical models can be used to analyze real-world phenomena such as glacier dynamics.
Transcribed Image Text:**Understanding Glacier Thickness through Differential Equations** In this lesson, we will explore how to determine the thickness of a glacier using differential equations. The glacier thickness is represented by the function \( T(x) \), and is influenced by the variable \( \tau(x) \). ### Problem Statement We are given the glacier thickness differential equation with: \[ \tau(x) = 0.3x(1000 - x) \, \text{N/m} \] With parameters: - \( \rho = 917 \, \text{kg/m}^3 \) - \( g = 9.8 \, \text{m/s}^2 \) **Tasks:** 1. **Finding the Particular Solution:** - **Initial Condition:** \( T(0) = 0 \). - **Differential Equation:** \[ \frac{dT}{dx} = \frac{\tau}{\rho g} \] 2. **Analyzing Glacier Thickness:** - Calculate the glacier's thickness at 1 km. - Graph the function \( T(x) \) using Desmos, highlighting the solution point, and ensure the graph is appropriately scaled for clarity. ### Visual Explanation The equation indicates that the rate of change in glacier thickness, \( \frac{dT}{dx} \), is equal to the stress \( \tau \) divided by the product of density \( \rho \) and gravitational acceleration \( g \). #### Guidance for Graphing: - Use appropriate scaling in Desmos to visualize changes in \( T(x) \). - Highlight the point where \( x = 1 \) km to examine the glacier thickness at this position. By following these steps, students will gain a better understanding of how mathematical models can be used to analyze real-world phenomena such as glacier dynamics.
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