a. Celerity of the pressure wave b. Equivalent bulk modulus of water c. Pressure on the pipe after closure of the valve d. Time required to avoid water hammer e. Water hammer pressure of the velocity will decrease to 1.2m/s f. Maximum permissible discharge after the outlet valve closure.

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
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Assuming that pressure will increase at a uniform rate and there is no damping of
the pressure wave. Water from a reservoir that flows through a 650mm pipe at 1.8m/s
is completely stopped by a closure of a 160 m valve from the reservoir. The thickness of
the pipe is 25mm, bulk modulus of water is 2.2x10⁹ Pa and E of steel is 1.4x10¹¹ Pa.
Determine the following:
a. Celerity of the pressure wave
b. Equivalent bulk modulus of water
c. Pressure on the pipe after closure of the valve
d. Time required to avoid water hammer
e. Water hammer pressure of the velocity will decrease to 1.2m/s
f. Maximum permissible discharge after the outlet valve closure.
ANSWER:
d) t = 0.256 sec.
e) Ph=pCAV = 749.8476 kPa
f) Q = AV = 0.597 m³/s
a) C = 1249.746m/s
b) k' = 1.562x10⁹ Pa
c) Ph=pCV = 2249.5428 kPa
Transcribed Image Text:Assuming that pressure will increase at a uniform rate and there is no damping of the pressure wave. Water from a reservoir that flows through a 650mm pipe at 1.8m/s is completely stopped by a closure of a 160 m valve from the reservoir. The thickness of the pipe is 25mm, bulk modulus of water is 2.2x10⁹ Pa and E of steel is 1.4x10¹¹ Pa. Determine the following: a. Celerity of the pressure wave b. Equivalent bulk modulus of water c. Pressure on the pipe after closure of the valve d. Time required to avoid water hammer e. Water hammer pressure of the velocity will decrease to 1.2m/s f. Maximum permissible discharge after the outlet valve closure. ANSWER: d) t = 0.256 sec. e) Ph=pCAV = 749.8476 kPa f) Q = AV = 0.597 m³/s a) C = 1249.746m/s b) k' = 1.562x10⁹ Pa c) Ph=pCV = 2249.5428 kPa
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